所有问题

我正在使用机器人来捕获屏幕截图。为了避免将 BufferedImage 写入磁盘然后将其重新加载到 Mat 中的不必要 I/O，我尝试使用以下代码将 BufferedImage 直接加载到 Mat 中。

我收到此错误：

我该如何规避这个问题？

我有一个具有这些尺寸（150,2）的矩阵，我想将每一行复制 N 次。我用一个例子来说明我的意思。

输入：

假设 N = 3，我想要这个输出：

谢谢你。

我有 2 个域，旧域是 mjvandco.co.uk，他希望这个重定向到 mjvlaw.co.uk。我都指向同一个网络空间，但是当我使用https://httpstatus.io/测试 URL 时，我得到了不同的结果。

我的 htaccess 中有以下内容以及其他内容，但这是重定向内容：

现在唯一不正确的 URL 是这个：http ://www.mjvlaw.co.uk/ 。我用过这个网站

https://mjvlaw.co.uk - 转到https://www.mjvlaw.co.uk
http://mjvlaw.co.uk - 转到https://www.mjvlaw.co.uk
http:// www.mjvlaw.co.uk - 不工作，因为不去
https://www.mjvlaw.co.uk - 很好

但是，当我对旧域做同样的事情时，它一切正常，下面的每一个也去https://www.mjvlaw.co.uk。
https://www.mjvandco.co.uk
https://mjvandco.co.uk
http://mjvandco.co.uk
http://www.mjvandco.co.uk

我在这里做傻事吗？我是否应该创建另一个网站空间并为旧域创建一个文件夹，以及当前域的文件夹是什么，并且每个文件夹都有自己的 htaccess 文件？
谢谢。大约一个月前我又做了一张票，但我不知道如何更改问题，所以我为类似的票道歉。

当我运行此代码时，出现“分段错误（核心转储）”。显然它来自 wait() 部分，但我无法弄清楚。

我有 2 个集合：电影和用户。在电影中我保存了有关电影的信息，例如在电影中扮演的演员的明星。我将此字段保存为电影集合中的数组。现在我想编写一个返回星星名称的查询。但是这个名称字段保存在用户集合中。如何从另一个集合中提取数据到这个集合？我写了这个函数，但它是错误的，stars_doc 是空的。这是我的功能：

在这个链接中我写了我的数据库模型。

刚开始使用 boost 测试框架。使用 Ubuntu + gcc（如果重要，可以通过新事物在 Windows 上运行）。当我运行测试时，我得到了这个：

我将如何找到我的代码中发生的位置？消息给出的唯一指示指向测试中的一行。有问题的行只是：

我相当确定问题发生在matches()函数内部的某个地方（可能有很多层次），但是......在哪里？

如果有人正在阅读本文，则“重复”答案都不起作用；显然人们在没有考虑上下文的​​情况下关闭了它。

Boost Test Framework 将信号处理程序替换为自己的（并在执行每个测试之前完成）。这意味着在每个测试开始时，您需要替换信号处理程序。我最终得到了这样的东西......

一些标题：

一些源文件：

然后SignalToStacktraceScope在每个测试功能的顶部放置一个（或包装BOOST_TEST_CASE宏以添加它）。在测试开始时做一次不会有帮助，因为 Boost 会继续替换它。

在此处输入图像描述

如何在给定图片的图像上添加这种类型的框架

We have integrated AutoDesk Forge Viewer. We are sending a request to the Forge API's for conversion (using Model derivative API). After closing the Viewer, If we need to show the same file again, Currently we are posting the dwg file again for conversion to view it.

Instead is there a way so save the svf file in my local system so that I need not call the Forge web service twice for the same file.

According to the pricing, for every simple conversion job, its going to cost 0.2 credits.

Please suggest how I can avoid this same conversion second and n number of times.

Thank you,

Shiva Kumar

I try to load the same .xml file in project target and unit test target.

It seems to be a similar problem like this question: Xcode. Image resources added to a test target are not copied into the tests bundle

In project target, this code snipped worked fine. I just have to add the "xmlString.xml" file to "Copy Files" (see image 1).

If I run the code snipped in unit test target, I get an error because the .xml file can not be found. I tried to add the .xml file to the "Copy Bundle Resources" without any success (see image 2).

The only way to get it working is to use the absolute path

Is there a way to use the Bundle.main.path(forResource: "xmlString", ofType: "xml") function instead of the absolute path?

Thanks in advance!

不确定使用 @rename 指令的所有方法。

我正在尝试重命名一个方法

至：

使用该指令会给我警告，但自动修复不处理参数名称。有没有办法格式化指令，以便自动修复适用于参数名称更改？

My code to create a nested dictionary with keys a unique list of users (keys from users) but using keys from movies to replace values of movies IDs (first item of value list from users) and keeping scores (second item of value list from users) is:

users_preference = {k: list(set().union((*map(lambda x: [x for x in movies.values()], v[0])) )) for k, v in users.items() }

But this returns all movies for each user, and I don't know how to add scores to this. Could you please help? Thank you.

The expected output is similar to:

我的问题是如何制作一个用户界面，用户可以通过拖动路径上的锚点来修改复杂的路径。请注意- 例如，Konvajs 文档中此示例中的贝塞尔曲线的控制点不在路径本身，而我更喜欢复杂路径上的锚点。

我将尝试修改在这个问题中创建的曲线。

这是一个绘制示例路径的片段。任何人都可以帮助我吗？稍微向下滚动片段窗口，然后单击矩形以查看路径动画。

另外，任何人都可以建议为什么在动画运行之前绘制曲线的一部分？

I am trying to implement a simplex algorithm following the rules I was given at my optimization course. The problem is

All vectors are assumes to be columns, ' denotes the transpose. The algorithm should also return the solution to dual LP. The rules to follow are:

Here, A_J denotes columns from A with indices in J and x_J, x_K denotes elements of vector x with indices in J or K respectively. Vector a_s is column s of matrix A.

Now I do not understand how this algorithm takes care of condition x >= 0, but I decided to give it a try and follow it step by step. I used Matlab for this and got the following code.

Functions findpositive(x) and findnegative(x, S) return the first index of positive or negative value in x. S is the set of indices, over which we look at. If S is omitted, whole vector is checked. Semicolons are omitted for debugging purposes.

The problem I tested this code on is

The reason for zeros(1,3) and eye(3) is that the problem is inequalities and we need slack variables. I have set starting basis to [4 5 6] because the notes say that starting basis should be set to slack variables.

Now, what happens during execution is that on first run of while, variable with index 1 enters basis (in Matlab, indices go from 1 on) and 4 exits it and that is reasonable. On the second run, 2 enters the basis (since it is the smallest index such that c(idx) < 0 and 1 leaves it. But now on the next iteration, 1 enters basis again and I understand why it enters, because it is the smallest index, such that c(idx) < 0. But here the looping starts. I assume that should not have happened, but following the rules I cannot see how to prevent this.

I guess that there has to be something wrong with my interpretation of the notes but I just cannot see where I am wrong. I also remember that when we solved LP on the paper, we were updating our subjective function on each go, since when a variable entered basis, we removed it from the subjective function and expressed that variable in subj. function with the expression from one of the equalities, but I assume that is different algorithm.

Any remarks or help will be highly appreciated.

为什么第一次有效，第二次无效？第一个做了交换，但第二个没有。我正在传递对函数的引用。为什么这不起作用？

我有很多标记的谷歌地图。这是我的代码：

我有一张地图和上面的标记。还行吧！

单击链接 obj-1 或 obj-2 后，我想：

如果用户点击链接“Atrakcja 1 pl” - 则地图位于带有标题 Atrakcja 1 pll 的标记的中心，并且他的提示将可见。

有谁知道如何在我的代码中做到这一点？

Hi I am currently attempting to learn C and I was wondering if there is a way to attain polymorphism in structures which contain a list of other different type of structures?

An example case of this is as such:

So far my approach to this problem has been solved with void pointer arrays of a tuple structure which contains a enum type which identifies the structure as well as the structure itself and then in a potential update function a fairly ugly switch statement has to be implemented with a case for each specific type.

Is there a better way to do this? As the switch approach will get fairly crazy pretty fast if there are a lot of different types within the array. which means one must explicitly add cases for each type and every case does exactly the same thing, which in this case is call a function pointer named "update".

重建 xamarin forms android 项目时出现以下错误。

/Library/Frameworks/Mono.framework/External/xbuild/Xamarin/Android/Xamarin.Android.Common.targets(2,2)：错误 XA0000：无法确定“v8.1”的 $(TargetFrameworkVersion) 的 API 级别。(XA0000) (Myproject.Android)

在其他一些线程中发现了相同的问题。那里的解决方案是打开 .csproj 文件并将 AndroidUseLatestPlatformSdk 从 True 更改为 False，然后重建。我在这里和这里找到了这个解决方案。

但是不知道需要修改哪个.csproj文件？有人能说的更清楚吗？

如果我声明一个常量变量

控制台显示值为 101

但是当我写这样的代码时：

有一个编译时错误：

第二种情况和第一种情况有区别吗？

我目前使用 Intellij，事实证明我正在尝试连接到 MySQL 数据库，但是在添加库并使用与 MariaDB 驱动程序完美配合的连接类之后，我发现问题标题中的错误

这些是我发送到我的班级连接的值

c= new conexion("jdbc:mysql://", "127.0.0.1/", "root", "", "sanciones"); c.conectar();

然后我详细介绍了连接类构造函数

更新

驱动版本 com.mysql.jdbc_5.1.5 不允许隐式加载驱动，因为 META-INF 中缺少 Services 子文件夹及其对应的内容，即使是 JDBC4，在 mysql 手册中都说有可能，至少在这个特定版本中不是，问候

我的问题是，当我在移动设备上查看该网站时，我看不到子菜单。

例如：我点击“Alaplap”菜单，然后它显示子菜单，“Intel alaplap”和“amd alaplap”。但是“Intel alaplap”也有一个子菜单，我在移动设备上看不到。

您可以在这里查看我的演示站点：我的演示站点

I have @ControllerAdvice annotated class, which is handling BadRequestException extends RuntimeException exception.

Now suppose that I have endpoint:

In case of unwanted scenario, endpoint throws BadRequestException (with HTTP Status 400) which constructs error JSON object as following:

Is there any way to document case like this using Spring REST Docs ?

This is example of my approach:

In this case test passes, but no documentation (.adoc) files are created.

When I try something like this:

test fails because NestedServletException was thrown caused by BadRequestException, and again there is no documentation created.

I have a legacy code which have dozen database calls to populate a report, it takes noticeable amount of time which I try to reduce using CompletableFuture.

I have some doubts that I do things correctly and not overuse this technology.

My code now looks like this:

1. Start asynchronous population of document sections with many database calls inside each methods

   /li>

2. Then I'm arranging futures in specific order in arrayList and joining all of them to make sure that my code will run further only when all futures are finished.

   /li>

3. Then I'm populating PDF document itself with its pieces

   return document

My concerns are:

1) Is it okay to create and instantiate many Completable Futures in such way? Order them in required sequence in arrayList, join them to make sure that they are all finished, and then get result by casting them into specific object?

2) Is it okay to run without specifying an executor service but to rely on common ForkJoinPool? However this code runs in web container, so probably in order to use JTA I need to use container provided thread pool executor via JNDI?

3) If this code is surrounded in try-catch I should be able to catch CompletionException in main thread, right? Or In order to do that I should declare each features like following:

4) Is it possible to overuse CompletableFutures so they become a performance bottleneck itself? Like many futures waits one executor to start running? How to avoid that? Use container provided executor service? If yes, could someone please point me to some best practice on how to correctly configure executor service taking to account processors and memory amount?

5) A memory impact. I read in parallel thread that there can be a problem with OOME as many object are created and garbage collected. Is there a best practice on how to calculate correct amount of memory required for application?

Let "l" be the above mentioned list, with the above code I am able to rotate the first half [4,5,7] with the other half [9,10,12], getting the desired output [9, 10, 12, 4, 5, 7]. However what I am trying to do and I cannot figure out, is in the case when we have an odd number of elements. Let's say l = [4,5,7,8,9,10,12] I want the odd number that is in the middle, in this case [8], to remain in the middle, and the first half to rotate with the last half, getting the output in this case [9,10,12,8,4,5,7]

Thanks in advance.

I want to concatenate 2 lists in immutable.js.

Both lists have this structure: { id, value }

The algorithm concatenate should do this:

• If an ID exists in both list1 and list2 take the value from list2.

If Immutable.js has this functionality with another type (eg. Dictionary), I could also use that.

I'm trying to override the init() method of a CrawlSpider in order to be able to pass domain name and start page. However, I can't seem to pass the rules in.

I have tried the approach suggested here(Scrapy: Rules set inside __init__ are ignored by CrawlSpider), and defined rules before the super() method, but it doesn't seem to work.

Here is my spider:

I pass these values to the terminal, but it stops at the first page:

this is the log: