For each column of a matrix A consisting of '0' and '1', I would like to find the column indices of the first occurrence of '1' if exists. For example, if A is defined as:
A=[0 0 0 0;
0 0 0 1;
0 0 0 0;
0 0 0 1;
1 0 0 0;
0 1 0 1;
1 1 0 0]
then the result would be:
b=[5 6 2]
I'm searching for a solution without any 'for' or 'while' loops.
One solution I came up with:
[b,~]=find(cumsum(cumsum(A))==1)
Is there a more elegant way to do this?