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I have some MATLAB code that filters an input signal using filter:

CUTOFF = 0.05;
FS = 5000;
[b, a] = butter(1, CUTOFF / (FS / 2), 'high');
% b = [0.99996859, -0.99996859]
% a = [1.0, -0.99993717]
dataAfter = filter(b, a, dataBefore);

I'm trying to convert this code to C#. I have already got the butter function to work pretty fast, but now I'm stuck converting the filter function.

I have read the MATLAB filter documentation and Python Scipy.signal filter documentation, but there is a term present in the transfer function definition that I don't understand.

Here is the "rational transfer function" definition from the linked documentation:

        b[0] + b[1]z^(-1)  + ... + b[M]z^(-M)
Y(z) = _______________________________________ X(z)
        a[0] + a[1]z^(-1)  + ... + a[N]z^(-N)

Correct me if i'm wrong, but z is the current element of input data, and Y(z) is the output?

If the above this is true, what is X(z) in this equation?

I want to understand this to implement it in C#, if there is an equivalent option then please enlighten me.

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1 回答 1

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More About正如您所指出的，在 matlab 文档的部分中，它们描述了：

Z变换域中向量的滤波器操作的输入-输出描述是一个有理传递函数。有理传递函数的形式为，

        b[0] + b[1]z^(-1)  + ... + b[M]z^(-M)
Y(z) = _______________________________________ X(z)
        a[0] + a[1]z^(-1)  + ... + a[N]z^(-N)

重新排列： 

       Y(z)   b[0] + b[1]z^(-1)  + ... + b[M]z^(-M)
H(z) = ____ = _______________________________________
       X(z)   a[0] + a[1]z^(-1)  + ... + a[N]z^(-N)

因此，X(z)是z-domain输入向量的变换x（参见 参考资料Digital Filter）。值得一提的是，同样在文档中，他们给出了传递函数的另一种表示形式difference equation

这更适合移植到代码中。中的一种可能实现C#方式是 ( using this answer as reference)

public static double[] Filter(double[] b, double[] a, double[] x)
{
   // normalize if a[0] != 1.0. TODO: check if a[0] == 0
   if(a[0] != 1.0)
   {
       a = a.Select(el => el / a[0]).ToArray();
       b = b.Select(el => el / a[0]).ToArray();
   }

   double[] result = new double[x.Length];
   result[0] = b[0] * x[0];
   for (int i = 1; i < x.Length; i++)
   {
       result[i] = 0.0;
       int j = 0;
       if ((i < b.Length) && (j < x.Length))
       {
           result[i] += (b[i] * x[j]);
       }
       while(++j <= i)
       {
            int k = i - j;
            if ((k < b.Length) && (j < x.Length))
            {
                result[i] += b[k] * x[j];
            }
            if ((k < x.Length) && (j < a.Length))
            {
                result[i] -= a[j] * result[k];
            }
        }
    }
    return result;
}

司机：

static void Main(string[] args)
{
    double[] dataBefore = { 1, 2, 3, 4 };
    double[] b = { 0.99996859, -0.99996859 };
    double[] a = { 1.0, -0.99993717 };

    var dataAfter = Filter(b1, a, dataBefore);
}

输出 

Matlab dataAfter = [0.99996859 1.999874351973491  2.999717289867956  3.999497407630634]
CSharp dataAfter = [0.99996859 1.9998743519734905 2.9997172898679563 3.999497407630634]

更新
如果系数向量a和b具有固定长度 2 过滤函数可以简化为：

public static double[] Filter(double[] b, double[] a, double[] x)
{
    // normalize if a[0] != 1.0. TODO: check if a[0] == 0
    if (a[0] != 1.0)
    {
        a = a.Select(el => el / a[0]).ToArray();
        b = b.Select(el => el / a[0]).ToArray();
    }

    int length = x.Length;
    double z = 0.0;
    double[] y = new double[length];    // output filtered signal

    double b0 = b[0];
    double b1 = b[1];
    double a1 = a[1];
    for (int i = 0; i < length; i++)
    {
        y[i] = b0 * x[i] + z;
        z = b1 * x[i] - a1 * y[i];
    }
    return y;
}
于 2018-06-29T15:55:41.490 回答