2

我正在使用 Eclipselink v2.3.3

我收到此错误

Error compiling the query [Credential.updateExistingCredentialNoPW: UPDATE Credential c SET c.active = :active, c.employee.address.streetAddress = :stadd, c.employee.address.city = :city, c.employee.address.province = :prov, c.employee.address.zip = :zip WHERE c.id = :id], line 1, column 46: invalid navigation expression [c.employee], cannot navigate association field [employee] in the SET clause target.

当我尝试运行我的代码时。

以下是阻止运行我的代码的受影响的命名查询

@NamedQuery(name = "Credential.updateExistingCredentialNoPW",
query = "UPDATE Credential c "
+ "SET c.active = :active, "
+ "c.employee.address.streetAddress = :stadd, "
+ "c.employee.address.city = :city, "
+ "c.employee.address.province = :prov, "
+ "c.employee.address.zip = :zip "
+ "WHERE c.id = :id"),

@NamedQuery(name = "Credential.updateExistingCredential",
query = "UPDATE Credential c "
+ "SET c.password = :pw, "
+ "c.active = :active, "
+ "c.employee.address.streetAddress = :stadd, "
+ "c.employee.address.city = :city, "
+ "c.employee.address.province = :prov, "
+ "c.employee.address.zip = :zip "
+ "WHERE c.id = :id"),

@NamedQuery(name = "Credential.updateSalary",
query = "UPDATE Credential c "
+ "SET c.employee.salary.value = :val WHERE c.id = :id")

这是我放置上面指定的所有命名查询的类

public class Credential implements Serializable {

private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(generator = "CRED_GEN", strategy = GenerationType.IDENTITY)
@Column(name = "CREDENTIAL_ID")
private long id;
// unique & not nullabe username
@Column(nullable = false, unique = true)
private String username;
@Column(nullable = false, name = "USER_KEY")
private String password;
@Column(nullable = false)
private boolean active;
@Column(nullable = false)
private int userLevel;
@OneToOne(cascade = CascadeType.PERSIST, fetch = FetchType.EAGER)
private Employee employee;

public Credential() {
}

public Credential(String username, String password, boolean active,
        int userLevel, Employee employee) throws NoSuchAlgorithmException {
    this.username = username;
    this.setPassword(password);
    this.active = active;
    this.userLevel = userLevel;
    this.employee = employee;
}

public long getId() {
    return id;
}

public void setId(long id) {
    this.id = id;
}

public int getUserLevel() {
    return userLevel;
}

public void setUserLevel(int userLevel) {
    this.userLevel = userLevel;
}

public boolean isActive() {
    return active;
}

public void setActive(boolean active) {
    this.active = active;
}

public Employee getEmployee() {
    return employee;
}

public void setEmployee(Employee employee) {
    this.employee = employee;
}

public String getPassword() {
    return password;
}

public void setPassword(String password) throws NoSuchAlgorithmException {
    this.password = Cryptography.getHash(password);
}

public String getUsername() {
    return username;
}

public void setUsername(String username) {
    this.username = username;
}

我做错了吗？

4

2 回答 2

0

无法使用单个 sql 查询更新多个表。

请参阅https://forums.oracle.com/forums/thread.jspa?threadID=2223393。

所以 Eclipselink 也不可能。

您必须将其拆分为两个查询，或者更好地使用设置器。

于 2012-09-26T05:58:22.293 回答
0

你不能。要么使用 SQL 查询，要么使用 Java 代码：

Credential c = em.find(Credential.class, credentialId);
c.setActive(active);
c.getEmployee().getAddress().setStreet(street);
...
于 2012-09-26T05:58:53.743 回答