4

我正在编写一个程序并尝试分解存储在数组中的数据，以使其运行得更快。我试图这样做：

    data_to_analyze=(1 2 3 4 5 6 7 8 9 10)
    #original array size
    dataSize=(${#data_to_analyze[@]})

    #half of that size
    let samSmall="$dataSize/2"

    #the other half
    let samSmall2=("$dataSize - $samSmall -1")

    #the first half
    smallArray=("${data_to_analyze[@]:0:$samSmall}")

    #the rest
    smallArray2=("${data_to_analyze[@]:$samSmall:$samSmall2}")

    #an array of names(which correspond to arrays)
    combArray=(smallArray smallArray2)
    sizeComb=(${#combArray[@]})

    #for the length of the new array
    for ((i=0; i<= $sizeComb ; i++)); do
        #through first set of data and then loop back around for the second arrays data? 
        for sample_name in ${combArray[i]}; do
            command
            wait
            command
            wait
        done

我想这样做只是首先将第一个数据数组提供给 for 循环。当第一个数组完成后，它应该再次通过第二个数组集。

这给我留下了两个问题。combArray 真的会传递两个较小的数组吗？还有更好的方法吗？

4

2 回答 2

5

您可以创建一个看起来像数组引用的字符串，然后使用它来间接访问引用数组的元素。它甚至适用于包含空格的元素！

combArray=(smallArray smallArray2)
for array in "${combArray[@]}"
do
    indirect=$array[@]    # make a string that sort of looks like an array reference
    for element in "${!indirect}"
    do
        echo "Element: $element"
    done
done
于 2012-07-09T22:35:45.367 回答
0 
#!/bin/bash
data_to_analyze=(1 2 3 4 5 6 7 8 9 10)
dataSize=${#data_to_analyze[@]}
((samSmall=dataSize/2,samSmall2=dataSize-samSmall))
smallArray=("${data_to_analyze[@]:0:$samSmall}")
smallArray2=("${data_to_analyze[@]:$samSmall:$samSmall2}")
combArray=(smallArray smallArray2)
sizeComb=${#combArray[@]}
for ((i=0;i<$sizeComb;i++));do
    eval 'a=("${'${combArray[i]}'[@]}")'
    for sample_name in "${a[@]}";do
        ...
    done 
done

编辑：删除 ${combArray[i]} 附近的双引号并将 <= 替换为 < in for

于 2012-07-10T07:14:50.080 回答