7

我正在尝试做与此 SQL 代码等效的操作

SELECT 
ID
SUM(CASE WHEN myProperty = 2 THEN 1 ELSE 0 END) as nbRowWithValueOf2,
SUM(CASE WHEN myProperty = 3 THEN 1 ELSE 0 END) as nbRowWithValueOf3
FROM Foo
GROUP BY ID

与休眠。

到目前为止我试过

queryable = queryable
    .Select(
        Projections.Group<Foo>(c => c.ID),
        Projections.Sum<Foo>(c => c.myProperty == MyEnum.Two ? 1 : 0)
        Projections.Sum<Foo>(c => c.myProperty == MyEnum.Three ? 1 : 0)
)

但这给了我以下错误:

无法从 IIF 确定成员((Convert(c.myProperty) = 2), 1, 0)

你有什么主意吗 ?

编辑 1:我可以通过 2 个查询获得结果,但我只想在 1 个查询中执行此操作。

编辑 2:我在这里使用 QueryOver。

4

1 回答 1

15

我认为这应该有效(QueryOver 语法):

queryover = queryover
    .Select(
        Projections.Group<Foo>(c => c.ID),
        Projections.Sum(
            Projections.Conditional(
                Restrictions.Where<Foo>(f => f.myProperty == MyEnum.Two),
                Projections.Constant(1),
                Projections.Constant(0))),
        Projections.Sum(
            Projections.Conditional(
                Restrictions.Where<Foo>(f => f.myProperty == MyEnum.Three),
                Projections.Constant(1),
                Projections.Constant(0))));

这应该为您提供以下 SQL:

SELECT this_.ID as y0_,
       sum((case
              when this_.myProperty = 2 /* @p0 */ then 1 /* @p1 */
              else 0 /* @p2 */
            end))               as y1_,
       sum((case
              when this_.myProperty = 3 /* @p3 */ then 1 /* @p4 */
              else 0 /* @p5 */
            end))               as y2_
FROM   [Foo] this_
GROUP  BY this_.ID
于 2012-03-19T17:11:15.110 回答