3

我一直在尝试为 monodroid 运行一个玩具意图服务，基本上脱离了这个源材料，我遇到了一些问题，我已经把它归结为广播接收器。我最怀疑的ACTION_RESP字符串。如果没有别的，我当然可以接受，也许可以确认这一点，也许是设置接收者可以看到的动作的正确方法。
所以，这就是我迄今为止所拥有的......

我的意向服务

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

using Android.App;
using Android.Content;
using Android.OS;
using Android.Runtime;
using Android.Views;
using Android.Widget;
using Android.Util;

namespace Mono_For_Android_Intent_Service
{
    [Service]
    public class TestIntentService : IntentService
    {
        public static String PARAM_IN_MSG = "imsg";
        public static String PARAM_OUT_MSG = "omsg";

        #region Constructor
        public TestIntentService()
            : base("TestIntentService")
        {
        }
        #endregion

        protected override void OnHandleIntent(Intent intent)
        {
            string msg = intent.GetStringExtra(PARAM_IN_MSG);
            //Do Stuff
            string result = msg + " " + DateTime.Now.ToString();
            Intent BroadcastIntent = new Intent(this,typeof(Mono_For_Android_Intent_Service.MainActivity.MyBroadcastReceiver));
            BroadcastIntent.SetAction(Mono_For_Android_Intent_Service.MainActivity.MyBroadcastReceiver.ACTION_RESP);
            BroadcastIntent.AddCategory(Intent.CategoryDefault);
            BroadcastIntent.PutExtra(PARAM_OUT_MSG,result);
            SendBroadcast(BroadcastIntent);
        }
    }
}

主要活动和广播接收器

using System;

using Android.App;
using Android.Content;
using Android.Runtime;
using Android.Views;
using Android.Widget;
using Android.OS;

namespace Mono_For_Android_Intent_Service
{
    [Activity(Label = "Mono_For_Android_Intent_Service", MainLauncher = true, Icon = "@drawable/icon")]
    public partial class MainActivity : Activity
    {
        private MyBroadcastReceiver Receiver;
        protected override void OnCreate(Bundle bundle)
        {
            base.OnCreate(bundle);

            // Set our view from the "main" layout resource
            SetContentView(Resource.Layout.Main);

            IntentFilter filter = new IntentFilter(MyBroadcastReceiver.ACTION_RESP);
            filter.AddCategory(Intent.CategoryDefault);
            Receiver = new MyBroadcastReceiver();
            RegisterReceiver(Receiver, filter);

            var button = FindViewById<Button>(Resource.Id.start);
            button.Click += (s,e)=>
            {
                Intent msgIntent= new Intent(this,typeof(TestIntentService));
                msgIntent.PutExtra(TestIntentService.PARAM_IN_MSG,"Me message, arh");
                Toast.MakeText(this, "Starting intent service!", ToastLength.Short).Show();
                StartService(msgIntent);

            };

            TextView txtView = FindViewById<TextView>(Resource.Id.status);
        }

        public class MyBroadcastReceiver : BroadcastReceiver
        {
            public static readonly string ACTION_RESP = "Mono_For_Android_Intent_Service.Intent.Action.MESSAGE_PROCESSED";
            public override void OnReceive(Context context, Intent intent)
            {
                Toast.MakeText(context, "Firing On Receive!", ToastLength.Short).Show();
                var activity = (MainActivity)context;
                TextView txtView = activity.FindViewById<TextView>(Resource.Id.status);
                txtView.Text = intent.GetStringExtra(TestIntentService.PARAM_OUT_MSG).ToString();
                Toast.MakeText(context, "On Receive complete!", ToastLength.Short).Show();
            }
        }
    }
}
  1. 我做错了吗？我接近了吗？我想我已经很接近了，但是，无论如何，如果我在 timbucktoo，我想知道......
  2. 如果是这样，发送和接收该广播的正确方法是什么？
4

1 回答 1

4

如果你想让你的广播接收器注册到系统中，你需要添加 [BroadcastReceiver] 属性。

样本：

https://github.com/xamarin/monodroid-samples/blob/master/ApiDemo/App/OneShotAlarm.cs

于 2011-12-31T03:39:18.880 回答