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我正在尝试将 XML 文档发送到页面 .asp，并得到答案，但出现以下错误：

System.UriFormatException：无效的 URI：URI 方案无效。在 System.Uri.CreateThis(String uri, Boolean dontEscape, UriKind uriKind) 在 System.Net.WebRequest.Create(String requestUriString) 在 GNS_ZalkarBank.GNSTaskServiceZalkarBank.CreateRequest(String requestData, String address) 在 GNS_ZalkarBank.GNSTaskServiceZalkarBank.SendRequest(String requestString) , String address) at GNS_ZalkarBank.GNSTaskServiceZalkarBank.processData(TaskInfo& taskInfo, Object& data) at Task.RegistryTemplate.RegistryTaskTemplate.execute(DataSet& dataSet)`

我用asp服务器脚本实现了一种向页面发送数据的方法：

private string SendRequest(String requestString, String address)
{
    address = "https://myadress/osmp_gni_xml.asp";
    HttpWebRequest httpRequest = this.CreateRequest(requestString, address);
    string response = GetResponse(httpRequest);
    return response;
}

private HttpWebRequest CreateRequest(string requestData, string address)
{
    HttpWebRequest request = (HttpWebRequest)WebRequest.Create(address);
    request.Method = "POST";
    //request.UserAgent = "Test";

    byte[] data = Encoding.UTF8.GetBytes(requestData);
    request.ContentType = "text/xml; encoding='utf-8'";
    request.ContentLength = data.Length;
    using (Stream dataStream = request.GetRequestStream())
    {
        dataStream.Write(data, 0, data.Length);
        dataStream.Close();
    }
    return request;
}

private string GetResponse(HttpWebRequest httpWebRequest)
{
    string responseString;
    HttpWebResponse response = (HttpWebResponse)httpWebRequest.GetResponse();
    using (Stream dataStream = response.GetResponseStream())
    {
        using (StreamReader reader = new StreamReader(dataStream))
        {
            responseString = reader.ReadToEnd();
        }
    }
    return responseString;
}

服务器端（脚本页面：osmp_gni_xml.asp）：

<%@ Language=VBScript CODEPAGE="65001"%>
<%    
    Sub AddSubNode(Parent, Name, Value)  
        Set subNode = XMLDoc.createElement(Name)  
        Parent.appendChild(subNode)  
        subNode.appendChild(XMLDoc.createTextNode(Value))  
    End Sub  

    Function Stream_BinaryToString(Binary, CharSet)
        Const adTypeText = 2
        Const adTypeBinary = 1

        'Create Stream object

        Dim BinaryStream 'As New Stream
        Set BinaryStream = CreateObject("ADODB.Stream")

        'Specify stream type - we want To save text/string data.

        BinaryStream.Type = adTypeBinary

       'Open the stream And write text/string data To the object

        BinaryStream.Open
        BinaryStream.Write Binary

        'Change stream type To binary

        BinaryStream.Position = 0
        BinaryStream.Type = adTypeText

        'Specify charset For the source text (unicode) data.

        If Len(CharSet) > 0 Then
            BinaryStream.CharSet = CharSet
        Else
            BinaryStream.CharSet = "us-ascii"
        End If

        'Open the stream And get binary data from the object

        Stream_BinaryToString = BinaryStream.ReadText
    End Function

    result=300
    OK="incomplete request"
    Dim PostData
    Dim biData

    PostData = ""
    If Request.TotalBytes>0 Then
        biData = Request.BinaryRead(Request.TotalBytes)

        PostData=Stream_BinaryToString(biData, "utf-8")

        ProvStr =  "Provider=sqloledb;Data Source=TEST;Initial Catalog=TESTOsmp;User Id=tests_osmp;Password=tests;"

        Set Conn = Server.CreateObject("ADODB.Connection")  
        Conn.Open ProvStr  
        Set cmdUA = Server.CreateObject("ADODB.Command")
        cmdUA.ActiveConnection = Conn
        cmdUA.CommandText = "GNI_Import"
        cmdUA.CommandType = 4 
        cmdUA.Parameters.Append cmdUA.CreateParameter("Reestr", 202, 1, 2000, PostData)

        Set RS = cmdUA.Execute
        result = RS("result") 

        RS.Close  
        Conn.Close 
        Set Conn = Nothing  
        Set RS = Nothing 
    End If

    'Create XML  

    Set XMLDoc = Server.CreateObject("Microsoft.XMLDOM")  

    Set pi = XMLDoc.createProcessingInstruction("xml"," version=""1.0"" encoding=""utf-8""")  
    XMLDoc.appendChild(pi)  

   'Main  

    Set mainNode = XMLDoc.createElement("response")  
    XMLDoc.appendChild(mainNode)  

    If result=0 Then
        OK="Ok"
    Else
        result=300
        OK="incomplete request"
    End If

    AddSubNode mainNode, "result",  result 
    AddSubNode mainNode, "comment", OK
    Response.ContentType = "text/xml"  
    Response.Write XMLDoc.XML  

    Set mainNode = Nothing 
    Set XMLDoc = Nothing   
%>

怎么了？

4

2 回答 2

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我怀疑您提供的代码不是有问题的代码，请参见：

private string SendRequest(String requestString, --> String address <--)
{
    --> address = "https://myadress/osmp_gni_xml.asp"; <--
    HttpWebRequest httpRequest = this.CreateRequest(requestString, address);
    string response = GetResponse(httpRequest);
    return response;
}

您将地址传递给该方法，然后在第一行对其进行硬接线。问题出在地址的格式上，但这段代码可能不存在。

可能发生的情况是，您正在从文件或数据库中读取地址，而作为人类，您会看到“https://myadress/osmp_gni_xml.asp”，因为您使用的是有缺陷的转义机制，但代码是什么看到是这样的：

https/:////myaddress//osmp_gni_xml.asp

这给出了同样的错误。

在您的实际代码中，您在 SendRequest 中覆盖它的地方的地址的确切值是多少

于 2012-09-07T13:22:17.977 回答
0

提供的错误文本来自这里：

private HttpWebRequest CreateRequest(string requestData, string address)
{
    HttpWebRequest request = (HttpWebRequest)WebRequest.Create(address); // <- THIS LINE
    ...
}

错误描述抱怨地址https://myadress/osmp_gni_xml.asp无效，https最可能的原因是连接问题。

尝试通过连接https但首先没有设置https服务器端是很常见的：验证地址是否可达，安全设置是否正确，以及排序。F12 开发者控制台（IE9 的一部分）、FireBug（Firefox 扩展）或 Fiddler（桌面应用程序）等控制台工具是找出外部连接发生情况的最佳工具。

于 2012-09-07T10:21:39.490 回答