我认为在 Android 上使用 XML 的最佳方式是使用VDT-XML 库
我的 XML 文件包含超过 60 000 行,VDT-XML 处理如下:
Nexus 5:2055 毫秒
Galaxy Note 4:2498 毫秒
您可以通过链接找到更多基准报告:VTD-XML Benchmark
XML 文件的简短示例
<database name="products">
<table name="category">
<column name="catId">20</column>
<column name="catName">Fruit</column>
</table>
<table name="category">
<column name="catId">31</column>
<column name="catName">Vegetables</column>
</table>
<table name="category">
<column name="catId">45</column>
<column name="catName">Rice</column>
</table>
<table name="category">
<column name="catId">50</column>
<column name="catName">Potatoes</column>
</table>
</database>
“build.gradle”文件的配置
dependencies {
compile files('libs/vtd-xml.jar')
}
源代码示例:
import com.ximpleware.AutoPilot;
import com.ximpleware.VTDGen;
import com.ximpleware.VTDNav;
String fileName = "products.xml";
VTDGen vg = new VTDGen();
if (vg.parseFile(fileName, true)) {
VTDNav vn = vg.getNav();
AutoPilot table = new AutoPilot(vn);
table.selectXPath("database/table");
while (table.iterate()) {
String tableName = vn.toString(vn.getAttrVal("name"));
if (tableName.equals("category")) {
AutoPilot column = new AutoPilot(vn);
column.selectElement("column");
while (column.iterate()) {
String text = vn.toNormalizedString(vn.getText());
String name = vn.toString(vn.getAttrVal("name"));
if (name.equals("catId")) {
Log.d("Category ID = " + text);
} else if (name.equals("catName")) {
Log.d("Category Name = " + text);
}
}
}
}
}
结果
Category ID = 20
Category Name = Fruit
Category ID = 31
Category Name = Vegetables
Category ID = 45
Category Name = Rice
Category ID = 50
Category Name = Potatoes
它对我有用,希望对你有帮助。