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我正在尝试使用此算法对月球图像进行拉普拉斯锐化:

公式的图像

我正在转换这张图片:

原始图像

但我不知道为什么我会得到这样的图像:

输出图像

这是我的代码:

import numpy as np

def readRawFile(name,row_size,column_size):
    imgFile = open(name,'rb')
    img = np.fromfile(imgFile, dtype = np.uint8, count = row_size * column_size)
    img = np.reshape(img,(-1,row_size))
    imgFile.close()
    return img

img = readRawFile("ass-3/moon464x528.raw", 464, 528)

width = img.shape[0]
height = img.shape[1]

img_pad = np.pad(img, ((1, 1), (1, 1)), 'edge')

w = np.array([1,1.2,1])

t1 = np.array([[0,-1,0],[-1,4,-1],[0,-1,0]])

edge_img = np.zeros((width, height))
edge_pad = np.pad(edge_img, ((1, 1), (1, 1)), 'constant')

for i in range(1,width-1):
    for j in range(1,height-1):
                
        edge_pad[i, j]=abs(np.sum((img_pad[i:i + 3, j:j + 3] * t1)*w))
        
        if edge_pad[i, j] < 0:
            edge_pad[i, j] = 0

out_img = img-edge_pad[1:edge_pad.shape[0]-1,1:edge_pad.shape[1]-1]
out_img.astype('int8').tofile("ass-3/moon-1.raw")

任何人都可以帮助我吗?

4

1 回答 1

4

我能够确定的问题很少:

  • 边缘图像允许具有正值和负值。
    删除abs, 并删除if edge_pad[i, j] < 0...
  • “窗口”img_pad[i:i + 3, j:j + 3]不是以 为中心[i, j],将其替换为:
    img_pad[i-1:i+2, j-1:j+2]
    (寻找二维离散卷积实现)。
  • 我认为w在公式中应该是一个负标量。
    替换w = np.array([1, 1.2, 1])w = -1.2
  • t1and的类型edge_padnp.float64, 的类型imgnp.uint8
    的类型img - edge_pad[1:edge_pad.shape[0] - 1, 1:edge_pad.shape[1] - 1]np.float64
    我们需要将值剪辑到范围 [0, 255] 并转换为np.uint8:
    out_img = np.clip(out_img, 0, 255).astype(np.uint8)

我看不到有关.raw格式的任何问题。
我将输入和输出替换为 PNG 图像格式,并使用 OpenCV 读取和写入图像。
OpenCV 的使用只是为了举例——你不需要使用 OpenCV。


这是一个“完整”的代码示例:

import numpy as np
import cv2

#def readRawFile(name, row_size, column_size):
#    imgFile = open(name, 'rb')
#    img = np.fromfile(imgFile, dtype=np.uint8, count=row_size * column_size)
#    img = np.reshape(img, (-1, row_size))
#    imgFile.close()
#    return img

#img = readRawFile("ass-3/moon464x528.raw", 464, 528)
img = cv2.imread('moon.png', cv2.IMREAD_GRAYSCALE)  # Read input image as grayscale.

width = img.shape[0]  # The first index is the height (the names are swapped)
height = img.shape[1]

img_pad = np.pad(img, ((1, 1), (1, 1)), 'edge')

#w = np.array([1, 1.2, 1])
w = -1.2  # I think w in the formula is supposed to be a negative a scalar

t1 = np.array([[0, -1, 0], [-1, 4, -1], [0, -1, 0]])

edge_img = np.zeros((width, height))
edge_pad = np.pad(edge_img, ((1, 1), (1, 1)), 'constant')

for i in range(1, width - 1):
    for j in range(1, height - 1):

        #edge_pad[i, j] = abs(np.sum((img_pad[i:i + 3, j:j + 3] * t1) * w))
        # Edge is allowed to be negative.
        edge_pad[i, j] = np.sum(img_pad[i-1:i+2, j-1:j+2] * t1) * w

        #if edge_pad[i, j] < 0:
        #    edge_pad[i, j] = 0

# img tyep is uint8 and edge_pad is float64, the result is float64
out_img = img - edge_pad[1:edge_pad.shape[0] - 1, 1:edge_pad.shape[1] - 1]
out_img = np.clip(out_img, 0, 255).astype(np.uint8)  # Clip range to [0, 255] and cast to uint8

#out_img.astype('int8').tofile("ass-3/moon-1.raw")

cv2.imwrite('out_img.png', out_img)  # Save out_img as PNG image file

# Show the input and the output images for testing
cv2.imshow('img', img)
cv2.imshow('edge_pad', (edge_pad-edge_pad.min())/(edge_pad.max() - edge_pad.min()))
cv2.imshow('out_img', out_img)
cv2.waitKey()
cv2.destroyAllWindows()

结果:

img
在此处输入图像描述

out_img
在此处输入图像描述

edge_pad(线性对比拉伸后):
在此处输入图像描述

于 2021-06-26T13:09:53.283 回答