5

我有从 1 到 180 天的天数，从日期 $epoch='2020-05-11' 开始减少和增加日期。整个周期 = 365.25 天，最后将添加一个幅度、一个频率和一个相位，以创建一个正弦波。这不是附加的全部代码，但我需要每天将其转换为弧度或关联？如何解决这个问题，我通过互联网搜索了从度数到弧度的转换。

数据输入来自 bat 文件，进一步轻松进行更改：

C:\Strawberry\perl\bin\perl.exe D:\perl\ex4444.pl Peri_GPS ZAT1_GPS 2020-05-11 180
pause

和代码本身：

#!/usr/bin/perl
use Math::Random::OO::Normal;
use Time::Local;
use Time::Localtime;
use POSIX qw(strftime);

my $filename = 'D:\perl\program.txt';
    open (FH, '>', $filename) 
        or die $!;
        
my ($station1, $station2, $epoch, $count_day) = @ARGV; 

$day_a2 = -1;
$day_a1 = $day_a2 - $count_day;
$day_a3 = 1;
$day_a4 = $day_a3 + $count_day;

my ($year, $month, $day) = split('-', $epoch);

$epoch = timelocal(0, 0, 0, $day, $month-1, $year-1900);
$day_sec = 60*60*24;
$interval=$count_day*$day_sec;
$epoch1=$epoch-86400;
$epoch2=$epoch1-$interval;
$epoch3=$epoch+86400;
$epoch4=$epoch3+$interval;

@x1=(); @x2=();

for ($d = $day_a1; $d <= $day_a2; $d++){
    $epoch2 += $day_sec;
    push (@x1, $d);
    printf FH scalar(strftime " %Y %m %d %H %M", localtime($epoch2));
    printf FH " %14.4f  \n";
    close $FH;
}
for ($d = $day_a3; $d <= $day_a4; $d++){
    $epoch3 += $day_sec;
    push (@x2, $d);
    print FH scalar(strftime " %Y %m %d %H %M", localtime($epoch3));
    printf FH " %14.4f  \n";
    close $FH; 
}
4

1 回答 1

10

你有一个范围，你想找到这个范围的一小部分。这是简单的乘法。

use POSIX       qw( strftime );
use Time::Local qw( timelocal );

my $date = '2020-05-11';
my $num_steps = 11;

my ($y, $m, $d) = split(/-/, $date);
my $epoch = timelocal(0, 0, 0, $d, $m-1, $y-1900);

my $range = 365.25 * 24 * 60 * 60 / 2;

for my $step (-$num_steps..$num_steps) {
   my $fraction = $step / $num_steps;
   my $new_epoch = $epoch + $range * $fraction;
   say strftime("%F %T", localtime($new_epoch));
}

对于我的时区，输出

2019-11-10 08:00:00
2019-11-28 14:18:00
2019-12-16 20:36:00
2020-01-04 02:54:00
2020-01-22 09:12:00
2020-02-09 15:30:00
2020-02-27 21:48:00
2020-03-17 05:06:00
2020-04-04 11:24:00
2020-04-22 17:42:00
2020-05-11 00:00:00
2020-05-29 06:18:00
2020-06-16 12:36:00
2020-07-04 18:54:00
2020-07-23 01:12:00
2020-08-10 07:30:00
2020-08-28 13:48:00
2020-09-15 20:06:00
2020-10-04 02:24:00
2020-10-22 08:42:00
2020-11-09 14:00:00

请注意$fraction从 -1 到 +1 的简单变化？好吧，sin(x) 也是如此！

假设我们在程序中添加以下内容：

use constant PI => 3.14159265359;

$fraction = sin( $fraction * PI );

内置函数sin将弧度作为输入，因此人们会期望日期遵循以下分布：

sin(x) 从 -pi 到 +pi

该程序现在输出以下内容：

2020-05-11 00:00:00   0
2020-03-15 13:34:42
2020-01-24 14:44:14
2019-12-15 05:04:42
2019-11-19 06:31:09
2019-11-10 08:00:00  -1
2019-11-19 06:31:09
2019-12-15 05:04:42
2020-01-24 14:44:14
2020-03-15 13:34:42
2020-05-11 00:00:00   0
2020-07-06 10:25:17
2020-08-26 08:15:45
2020-10-05 17:55:17
2020-10-31 16:28:50
2020-11-09 14:00:00  +1
2020-10-31 16:28:50
2020-10-05 17:55:17
2020-08-26 08:15:45
2020-07-06 10:25:17
2020-05-10 23:59:59   0
于 2020-09-08T06:43:49.093 回答