1

这是我的 API 请求

public IEnumerator Login(string bodyJsonString)
{
    Debug.Log(bodyJsonString);

    UnityWebRequest req = UnityWebRequest.Post("localhost:3000/login", bodyJsonString);
    req.SetRequestHeader("content-type", "application/json");
    yield return req.SendWebRequest();
    if (req.isNetworkError || req.isHttpError)
    {
        Debug.Log(req.error);
    }
    else
    {
        Debug.Log("Form upload complete!");
    }

}

它返回错误状态代码 500 并在服务器上返回错误 Unexpected token % in JSON at position 0","severity

这是我的协程调用

public void submitLogin()
{

    _username = userInputField.GetComponent<InputField>().text;
    _password = passwordInputField.GetComponent<InputField>().text;

    Debug.Log("username" + _username);
    Debug.Log("password" + _password);

    string body = "{'username':'" + _username + "','password','" + _password + "'}";

    //API Call
    authChexi = new Auth();
    StartCoroutine(authChexi.Login(body));
}

如果您对如何处理我的表单主体有任何想法，请告诉我。谢谢

4

1 回答 1

2

所以我更新了我的功能。我做了一些挖掘，终于解决了。我的错误确实是手动构建了一个 JSON。所以这是我的解决方案。

public void submitLogin()
{

    _username = userInputField.GetComponent<InputField>().text;
    _password = passwordInputField.GetComponent<InputField>().text;

    //API Call
    authChexi = new Auth();
    StartCoroutine(authChexi.Login(_username, _password));
}

为我的 json 对象创建了一个类 userdata

public class UserData 
{
    public string username;
    public string password;
    public string email;
}

并调用 API

public IEnumerator Login(string username, string password)
{
    //@TODO: call API login
    // Store Token
    // Add Token to headers

    var user = new UserData();
    user.username = username;
    user.password = password;

    string json = JsonUtility.ToJson(user);

    var req = new UnityWebRequest("localhost:3000/login", "POST");
    byte[] jsonToSend = new System.Text.UTF8Encoding().GetBytes(json);
    req.uploadHandler = (UploadHandler)new UploadHandlerRaw(jsonToSend);
    req.downloadHandler = (DownloadHandler)new DownloadHandlerBuffer();
    req.SetRequestHeader("Content-Type", "application/json");

    //Send the request then wait here until it returns
    yield return req.SendWebRequest();

    if (req.isNetworkError)
    {
        Debug.Log("Error While Sending: " + req.error);
    }
    else
    {
        Debug.Log("Received: " + req.downloadHandler.text);
    }

}

现在它就像一个魅力！

于 2020-03-26T21:39:34.227 回答