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我正在尝试使用 VB6 中的此代码循环获取所有 2011 年双周日期：

Dim HardDate As Date
Dim NumberOfDaysSince As Integer
Dim modulus As Integer
Dim DaysToNext As Integer
Dim nextpayday As Date
Dim x As Integer

x = 1
DateToday = Date
HardDate = Format(Now, "m/dd/yyyy")

Do While x <> 20
    NumberOfDaysSince = DateDiff("d", HardDate, DateToday)
    modulus = NumberOfDaysSince Mod 14
    DaysToNext = 15 - modulus
    nextpayday = Date + DaysToNext

    Debug.Print nextpayday
    HardDate = DateAdd("d", 1, nextpayday)
    DateToday = DateAdd("d", 10, HardDate)
    x = x + 1
Loop

但是，使用上面的代码不会产生持续的双周日期......

任何帮助都会很棒！

日期示例

Pay Begin Date | Pay End Date | Check Date | Posts
-------------------------------------------------------------------
1/14/2011      | 1/24/2011    | 2/10/2011  | 2/3/2011
1/28/2011      | 2/10/2011    | 2/24/2011  | 2/17/2011
2/11/2011      | 2/24/2011    | 3/10/2011  | 3/3/2011

大卫

4

1 回答 1

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假设您知道您想要的第一个日期是 2011 年，并且您知道您想要 26 个两周，那么代码可以非常简化。出于说明目的，将文本框“Text1”添加到表单，并在设计器中设置 MultiLine = True。我们将使用 2011 年 1 月 7 日作为开始日期：

Dim HardDate As Date
Dim x As Integer

x = 1
HardDate = "1/7/2011"
Text1.Text = HardDate
Do Until x = 26
    HardDate = DateAdd("d", 14, HardDate)
    Text1.Text = Text1.Text & vbCrLf & HardDate
    x = x + 1
Loop

文本框中显示的输出如下所示：

1/7/2011
1/21/2011
2/4/2011
2/18/2011
3/4/2011
...
12/23/2011
于 2011-03-16T18:13:45.527 回答