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我在我的应用程序中遇到了一个奇怪的行为：当我尝试设置服务前台时，手机（HTC G1 + Cyanogen Mod）重新启动。

当我不尝试将该服务置于前台时，它会起作用。

以下是涉案代码：

Notification notification = new Notification(R.drawable.icon,
    getText(R.string.ticker_text), System.currentTimeMillis());
    startForeground(SERVICE_NOTIFICATION_ID, notification);
Log.v(TAG, "Control service foregrounded.");

你能看出问题出在哪里吗？

如果需要更多数据，可以在 GitHub 上找到整个项目：https ://github.com/rbochet/Serval-Video-Discovery/tree/network-remote

谢谢。

4

1 回答 1

0

在此处查看此 Android API 演示。请注意，它调用的不是调用startForeground()，而是调用startForegroundCompat()一个包装器，该包装器根据新/旧 startForeground API 处理您的请求。

void handleCommand(Intent intent) {
        if (ACTION_FOREGROUND.equals(intent.getAction())) {
            ...

            // Set the icon, scrolling text and timestamp
            Notification notification = new Notification(R.drawable.stat_sample, text,
                    System.currentTimeMillis());

            // The PendingIntent to launch our activity if the user selects this notification
            PendingIntent contentIntent = PendingIntent.getActivity(this, 0,
                    new Intent(this, Controller.class), 0);

            // Set the info for the views that show in the notification panel.
            notification.setLatestEventInfo(this, getText(R.string.local_service_label),
                           text, contentIntent);

            startForegroundCompat(R.string.foreground_service_started, notification);
            ...
    }

这里是startForegroundCompat()：

/**
 * This is a wrapper around the new startForeground method, using the older
 * APIs if it is not available.
 */
void startForegroundCompat(int id, Notification notification) {
    // If we have the new startForeground API, then use it.
    if (mStartForeground != null) {
        mStartForegroundArgs[0] = Integer.valueOf(id);
        mStartForegroundArgs[1] = notification;
        invokeMethod(mStartForeground, mStartForegroundArgs);
        return;
    }

    // Fall back on the old API.
    mSetForegroundArgs[0] = Boolean.TRUE;
    invokeMethod(mSetForeground, mSetForegroundArgs);
    mNM.notify(id, notification);
}
于 2011-03-16T14:36:19.913 回答