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我正在使用 Apache CXF Web 服务和 Spring Integration，我现在不知道如何从您的 CXF 端点调用 Spring Integration 应用程序。

我有使用 Apache Camel 的经验，并且很容易解决这个问题......但在 Spring Integration 中我不知道......

我的行代码是：

  1. 在 webservices-definition-beans.xml 中：

    <!-- Load CXF modules from cxf.jar -->
<import resource="classpath:META-INF/cxf/cxf.xml"/>
<import resource="classpath:META-INF/cxf/cxf-extension-soap.xml"/>
<import resource="classpath:META-INF/cxf/cxf-servlet.xml"/>

<!--Exposing the HelloWorld service as a SOAP service -->
<bean id="jaxbBean"
      class="org.apache.cxf.jaxb.JAXBDataBinding"
      scope="prototype"/>

<bean id="jaxws-and-aegis-service-factory"
      class="org.apache.cxf.jaxws.support.JaxWsServiceFactoryBean"
      scope="prototype">
    <property name="dataBinding" ref="jaxbBean"/>
    <property name="serviceConfigurations">
    <list>
        <bean class="org.apache.cxf.jaxws.support.JaxWsServiceConfiguration"/>
        <bean class="org.apache.cxf.aegis.databinding.AegisServiceConfiguration"/>
        <bean class="org.apache.cxf.service.factory.DefaultServiceConfiguration"/>
    </list>
</property>
</bean>

<jaxws:endpoint id="helloWorld"
            serviceName="HelloWorldService"
            implementorClass="com.datys.cxf.HelloWorldService"
            address="/HelloWorld">
    <jaxws:serviceFactory>
        <ref bean="jaxws-and-aegis-service-factory"/>
    </jaxws:serviceFactory>
</jaxws:endpoint>

  2. 在 service-definition-beans.xml 中：

    <gateway id="HelloWorldService" 
         default-request-channel="requestStrings"
         default-reply-channel="replyStrings"             
         service-interface="com.datys.cxf.HelloWorldService">
    <method name="sayHello"/>
</gateway>

<channel id="requestStrings"/>
<channel id="replyStrings"/> 

<!--<channel id="filesOut"/>-->
<service-activator input-channel="requestStrings"
                   output-channel="filesOut"
                   ref="handler" method="handleString"/>

<file:outbound-channel-adapter id="filesOut" 
                               directory="file:D:/OUTPUT"/>

<beans:bean id="handler" class="org.springframework.integration.samples.filecopy.Handler"/>

但是，当我使用 client-webservices 部署和调用 Web 服务时，会返回此错误：

Exception in thread "main" javax.xml.ws.soap.SOAPFaultException: Could not instantiate service     class com.datys.cxf.HelloWorldService because it is an interface.
at com.sun.xml.internal.ws.fault.SOAP11Fault.getProtocolException(SOAP11Fault.java:171)
at com.sun.xml.internal.ws.fault.SOAPFaultBuilder.createException(SOAPFaultBuilder.java:94)
at com.sun.xml.internal.ws.client.sei.SyncMethodHandler.invoke(SyncMethodHandler.java:240)
at com.sun.xml.internal.ws.client.sei.SyncMethodHandler.invoke(SyncMethodHandler.java:210)
at com.sun.xml.internal.ws.client.sei.SEIStub.invoke(SEIStub.java:103)
at $Proxy29.sayHello(Unknown Source)
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1 回答 1

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可能最简单的选项是配置 <gateway>。这允许您提供可以注入端点并调用它来启动消息流的任何接口。在幕后，该接口的实现方式与 Spring 中的其他“ProxyFactoryBean”实现方式相同（例如，通过 RMI、HttpInvoker 等进行远程处理）。

这是参考手册中的相关部分：http: //static.springsource.org/spring-integration/docs/2.1.x/reference/htmlsingle/#gateway-proxy

于 2012-05-31T20:04:00.523 回答