我一直在做 c# 很长一段时间,从来没有遇到过一种简单的方法来新建一个哈希。
我最近熟悉了哈希的 ruby 语法,并且想知道,有没有人知道一种将哈希声明为文字的简单方法,而无需执行所有的 add 调用。
{ "whatever" => {i => 1}; "and then something else" => {j => 2}};
如果您使用的是 C# 3.0 (.NET 3.5),那么您可以使用集合初始化程序。它们不像 Ruby 那样简洁,但仍然是一个改进。
此示例基于MSDN 示例
var students = new Dictionary<int, StudentName>()
{
{ 111, new StudentName {FirstName="Sachin", LastName="Karnik", ID=211}},
{ 112, new StudentName {FirstName="Dina", LastName="Salimzianova", ID=317, }},
{ 113, new StudentName {FirstName="Andy", LastName="Ruth", ID=198, }}
};
当我无法使用 C# 3.0 时,我会使用一个帮助函数将一组参数转换为字典。
public IDictionary<KeyType, ValueType> Dict<KeyType, ValueType>(params object[] data)
{
Dictionary<KeyType, ValueType> dict = new Dictionary<KeyType, ValueType>((data == null ? 0 :data.Length / 2));
if (data == null || data.Length == 0) return dict;
KeyType key = default(KeyType);
ValueType value = default(ValueType);
for (int i = 0; i < data.Length; i++)
{
if (i % 2 == 0)
key = (KeyType) data[i];
else
{
value = (ValueType) data[i];
dict.Add(key, value);
}
}
return dict;
}
像这样使用:
IDictionary<string,object> myDictionary = Dict<string,object>(
"foo", 50,
"bar", 100
);
由于可以像这样指定 C# 3.0 (.NET 3.5) 哈希表文字:
var ht = new Hashtable {
{ "whatever", new Hashtable {
{"i", 1}
} },
{ "and then something else", new Hashtable {
{"j", 2}
} }
};
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace Dictionary
{
class Program
{
static void Main(string[] args)
{
Program p = new Program();
Dictionary<object, object > d = p.Dic<object, object>("Age",32,"Height",177,"wrest",36);//(un)comment
//Dictionary<object, object> d = p.Dic<object, object>();//(un)comment
foreach(object o in d)
{
Console.WriteLine(" {0}",o.ToString());
}
Console.ReadLine();
}
public Dictionary<K, V> Dic<K, V>(params object[] data)
{
//if (data.Length == 0 || data == null || data.Length % 2 != 0) return null;
if (data.Length == 0 || data == null || data.Length % 2 != 0) return new Dictionary<K,V>(1){{ (K)new Object(), (V)new object()}};
Dictionary<K, V> dc = new Dictionary<K, V>(data.Length / 2);
int i = 0;
while (i < data.Length)
{
dc.Add((K)data[i], (V)data[++i]);
i++;
}
return dc;
}
}
}