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我正在使用 firebase + angularfire2 测试谷歌地图。

Firebase 数据结构

{
  markers: 
      key1 : {lat:1, lng:2}
      key2 : {lat:3, lng:4}           
}

使用 JS + firebase,所有 3 个事件都运行良好。

var markers = database.ref('markers');
markers.on('child_added',  function(snapshot) {
    addMarkerUI(snapshot);
});  
markers.on('child_changed', function(snapshot){
    updateMarkerUI(snapshot);
});
markers.on('child_removed', function(snapshot, prevChildKey) {
    removeMarkerUI(snapshot);
});  

但是对于 angularfire2,它的表现非常不同。

itemsRef: AngularFireList<any>;

constructor(private db: AngularFireDatabase) { }

ngOnInit() {
    this.itemsRef = this.db.list('markers');
    this.itemsRef.snapshotChanges(['child_added', 'child_changed', 'child_removed'])
        .subscribe(actions => {
            console.log(actions);
            actions.forEach(action => {
                if (action.type === 'child_added') {// works
                    console.log(action)
                    console.log(action.type);
                    console.log(action.key);
                }

                if (action.type === 'child_changed') {// works
                    console.log(action)
                    console.log(action.type);
                    console.log(action.key);
                }

                if (action.type === 'child_removed') {// does not works
                    console.log(action)
                    console.log(action.type);
                    console.log(action.key);
                }
                // this.items.push(action.payload.val());
                // console.log(action.payload.val());
            });
        });

“child_removed”事件只返回没有删除子项的操作。为 removeMarkerUI 方法实现“child_removed”的最佳实践是什么?

4

1 回答 1

1

使用 stateChanges 而不是 snapshotChanges

items: Observable<any[]>;
itemsRef: AngularFireList<any>;

constructor(private db: AngularFireDatabase) {}

ngOnInit() {
    this.items$ = this.db.list('markers');
    this.items$.stateChanges(['child_added', 'child_changed', 'child_removed'])
      .subscribe(action => {
        if (action.type === 'child_added') {
          console.log('I was added', action, action.payload.val())
        }

        if (action.type === 'child_changed') {
          console.log('I was modified', action, action.payload.val())
        }

        if (action.type === 'child_removed') {
          console.log('I was deleted', action, action.payload.val())
        }

      });
}
于 2018-03-16T04:15:26.423 回答