44

我有Books,Chapters和的模型Pages。它们都是由 a 编写的User

from django.db import models

class Book(models.Model)
    author = models.ForeignKey('auth.User')

class Chapter(models.Model)
    author = models.ForeignKey('auth.User')
    book = models.ForeignKey(Book)

class Page(models.Model)
    author = models.ForeignKey('auth.User')
    book = models.ForeignKey(Book)
    chapter = models.ForeignKey(Chapter)

我想做的是复制现有的Book并将其更新User给其他人。皱纹是我还想将所有相关的模型实例复制到-Book一切都是如此!ChaptersPages

看 a 时事情变得非常棘手Page-新对象不仅需要更新Pagesauthor字段,而且还需要指向新Chapter对象!

Django 支持开箱即用的方式吗?复制模型的通用算法是什么样的?

干杯,

约翰


更新:

上面给出的类只是说明我遇到的问题的一个例子!

4

17 回答 17

18

这在 Django 1.3 中不再有效,因为 CollectedObjects 已被删除。请参阅变更集 14507

我在 Django Snippets 上发布了我的解决方案。它很大程度上基于django.db.models.query.CollectedObject用于删除对象的代码:

from django.db.models.query import CollectedObjects
from django.db.models.fields.related import ForeignKey

def duplicate(obj, value, field):
    """
    Duplicate all related objects of `obj` setting
    `field` to `value`. If one of the duplicate
    objects has an FK to another duplicate object
    update that as well. Return the duplicate copy
    of `obj`.  
    """
    collected_objs = CollectedObjects()
    obj._collect_sub_objects(collected_objs)
    related_models = collected_objs.keys()
    root_obj = None
    # Traverse the related models in reverse deletion order.    
    for model in reversed(related_models):
        # Find all FKs on `model` that point to a `related_model`.
        fks = []
        for f in model._meta.fields:
            if isinstance(f, ForeignKey) and f.rel.to in related_models:
                fks.append(f)
        # Replace each `sub_obj` with a duplicate.
        sub_obj = collected_objs[model]
        for pk_val, obj in sub_obj.iteritems():
            for fk in fks:
                fk_value = getattr(obj, "%s_id" % fk.name)
                # If this FK has been duplicated then point to the duplicate.
                if fk_value in collected_objs[fk.rel.to]:
                    dupe_obj = collected_objs[fk.rel.to][fk_value]
                    setattr(obj, fk.name, dupe_obj)
            # Duplicate the object and save it.
            obj.id = None
            setattr(obj, field, value)
            obj.save()
            if root_obj is None:
                root_obj = obj
    return root_obj

对于 django >= 2应该有一些最小的变化。所以输出将是这样的:

def duplicate(obj, value=None, field=None, duplicate_order=None):
    """
    Duplicate all related objects of obj setting
    field to value. If one of the duplicate
    objects has an FK to another duplicate object
    update that as well. Return the duplicate copy
    of obj.
    duplicate_order is a list of models which specify how
    the duplicate objects are saved. For complex objects
    this can matter. Check to save if objects are being
    saved correctly and if not just pass in related objects
    in the order that they should be saved.
    """
    from django.db.models.deletion import Collector
    from django.db.models.fields.related import ForeignKey

    collector = Collector(using='default')
    collector.collect([obj])
    collector.sort()
    related_models = collector.data.keys()
    data_snapshot = {}
    for key in collector.data.keys():
        data_snapshot.update(
            {key: dict(zip([item.pk for item in collector.data[key]], [item for item in collector.data[key]]))})
    root_obj = None

    # Sometimes it's good enough just to save in reverse deletion order.
    if duplicate_order is None:
        duplicate_order = reversed(related_models)

    for model in duplicate_order:
        # Find all FKs on model that point to a related_model.
        fks = []
        for f in model._meta.fields:
            if isinstance(f, ForeignKey) and f.remote_field.related_model in related_models:
                fks.append(f)
        # Replace each `sub_obj` with a duplicate.
        if model not in collector.data:
            continue
        sub_objects = collector.data[model]
        for obj in sub_objects:
            for fk in fks:
                fk_value = getattr(obj, "%s_id" % fk.name)
                # If this FK has been duplicated then point to the duplicate.
                fk_rel_to = data_snapshot[fk.remote_field.related_model]
                if fk_value in fk_rel_to:
                    dupe_obj = fk_rel_to[fk_value]
                    setattr(obj, fk.name, dupe_obj)
            # Duplicate the object and save it.
            obj.id = None
            if field is not None:
                setattr(obj, field, value)
            obj.save()
            if root_obj is None:
                root_obj = obj
    return root_obj
于 2009-01-14T00:28:16.800 回答
11

这是复制对象的简单方法。

基本上:

(1) 将原始对象的 id 设置为 None:

book_to_copy.id = 无

(2) 更改'author'属性并保存对象:

book_to_copy.author = new_author

book_to_copy.save()

(3) 执行 INSERT 而不是 UPDATE

(它没有解决在页面中更改作者的问题——我同意关于重构模型的评论)

于 2010-06-25T18:20:17.107 回答
9

我没有在 django 中尝试过,但 python 的deepcopy可能只适合你

编辑:

如果您实现功能,您可以为模型定义自定义复制行为:

__copy__() and __deepcopy__()
于 2009-01-12T22:24:51.260 回答
9

这是http://www.djangosnippets.org/snippets/1282/的编辑

它现在与在 1.3 中取代 CollectedObjects 的 Collector 兼容。

我并没有真正对此进行过多的测试,但确实使用具有大约 20,000 个子对象的对象对其进行了测试,但外键深度只有大约三层。当然,使用风险自负。

对于阅读这篇文章的雄心勃勃的人,您应该考虑将 Collector 子类化(或复制整个类以消除对 django API 的此未发布部分的依赖)到一个名为“DuplicateCollector”之类的类,并编写一个有效的 .duplicate 方法类似于 .delete 方法。这将真正解决这个问题。

from django.db.models.deletion import Collector
from django.db.models.fields.related import ForeignKey

def duplicate(obj, value=None, field=None, duplicate_order=None):
    """
    Duplicate all related objects of obj setting
    field to value. If one of the duplicate
    objects has an FK to another duplicate object
    update that as well. Return the duplicate copy
    of obj.
    duplicate_order is a list of models which specify how
    the duplicate objects are saved. For complex objects
    this can matter. Check to save if objects are being
    saved correctly and if not just pass in related objects
    in the order that they should be saved.
    """
    collector = Collector({})
    collector.collect([obj])
    collector.sort()
    related_models = collector.data.keys()
    data_snapshot =  {}
    for key in collector.data.keys():
        data_snapshot.update({ key: dict(zip([item.pk for item in collector.data[key]], [item for item in collector.data[key]])) })
    root_obj = None

    # Sometimes it's good enough just to save in reverse deletion order.
    if duplicate_order is None:
        duplicate_order = reversed(related_models)

    for model in duplicate_order:
        # Find all FKs on model that point to a related_model.
        fks = []
        for f in model._meta.fields:
            if isinstance(f, ForeignKey) and f.rel.to in related_models:
                fks.append(f)
        # Replace each `sub_obj` with a duplicate.
        if model not in collector.data:
            continue
        sub_objects = collector.data[model]
        for obj in sub_objects:
            for fk in fks:
                fk_value = getattr(obj, "%s_id" % fk.name)
                # If this FK has been duplicated then point to the duplicate.
                fk_rel_to = data_snapshot[fk.rel.to]
                if fk_value in fk_rel_to:
                    dupe_obj = fk_rel_to[fk_value]
                    setattr(obj, fk.name, dupe_obj)
            # Duplicate the object and save it.
            obj.id = None
            if field is not None:
                setattr(obj, field, value)
            obj.save()
            if root_obj is None:
                root_obj = obj
    return root_obj

编辑:删除了调试“打印”语句。

于 2011-05-19T19:51:02.983 回答
4

在 Django 1.5 中,这对我有用:

thing.id = None
thing.pk = None
thing.save()
于 2013-05-22T19:28:37.707 回答
4

使用上面的 CollectedObjects 片段不再有效,但可以通过以下修改来完成:

from django.contrib.admin.util import NestedObjects
from django.db import DEFAULT_DB_ALIAS

collector = NestedObjects(using=DEFAULT_DB_ALIAS)

而不是 CollectorObjects

于 2016-01-23T03:46:12.983 回答
4

我在 Django 2.2/Python 3.6 中尝试了一些答案,它们似乎没有复制一对多和多对多相关对象。此外,许多包括对数据结构的硬编码/合并预知。

我写了一种方法来以更通用的方式执行此操作,处理一对多和多对多相关对象。包括评论,如果您有建议,我希望对其进行改进:

def duplicate_object(self):
    """
    Duplicate a model instance, making copies of all foreign keys pointing to it.
    There are 3 steps that need to occur in order:

        1.  Enumerate the related child objects and m2m relations, saving in lists/dicts
        2.  Copy the parent object per django docs (doesn't copy relations)
        3a. Copy the child objects, relating to the copied parent object
        3b. Re-create the m2m relations on the copied parent object

    """
    related_objects_to_copy = []
    relations_to_set = {}
    # Iterate through all the fields in the parent object looking for related fields
    for field in self._meta.get_fields():
        if field.one_to_many:
            # One to many fields are backward relationships where many child 
            # objects are related to the parent. Enumerate them and save a list 
            # so we can copy them after duplicating our parent object.
            print(f'Found a one-to-many field: {field.name}')

            # 'field' is a ManyToOneRel which is not iterable, we need to get
            # the object attribute itself.
            related_object_manager = getattr(self, field.name)
            related_objects = list(related_object_manager.all())
            if related_objects:
                print(f' - {len(related_objects)} related objects to copy')
                related_objects_to_copy += related_objects

        elif field.many_to_one:
            # In testing, these relationships are preserved when the parent
            # object is copied, so they don't need to be copied separately.
            print(f'Found a many-to-one field: {field.name}')

        elif field.many_to_many:
            # Many to many fields are relationships where many parent objects
            # can be related to many child objects. Because of this the child
            # objects don't need to be copied when we copy the parent, we just
            # need to re-create the relationship to them on the copied parent.
            print(f'Found a many-to-many field: {field.name}')
            related_object_manager = getattr(self, field.name)
            relations = list(related_object_manager.all())
            if relations:
                print(f' - {len(relations)} relations to set')
                relations_to_set[field.name] = relations

    # Duplicate the parent object
    self.pk = None
    self.save()
    print(f'Copied parent object ({str(self)})')

    # Copy the one-to-many child objects and relate them to the copied parent
    for related_object in related_objects_to_copy:
        # Iterate through the fields in the related object to find the one that 
        # relates to the parent model.
        for related_object_field in related_object._meta.fields:
            if related_object_field.related_model == self.__class__:
                # If the related_model on this field matches the parent
                # object's class, perform the copy of the child object and set
                # this field to the parent object, creating the new
                # child -> parent relationship.
                related_object.pk = None
                setattr(related_object, related_object_field.name, self)
                related_object.save()

                text = str(related_object)
                text = (text[:40] + '..') if len(text) > 40 else text
                print(f'|- Copied child object ({text})')

    # Set the many-to-many relations on the copied parent
    for field_name, relations in relations_to_set.items():
        # Get the field by name and set the relations, creating the new
        # relationships.
        field = getattr(self, field_name)
        field.set(relations)
        text_relations = []
        for relation in relations:
            text_relations.append(str(relation))
        print(f'|- Set {len(relations)} many-to-many relations on {field_name} {text_relations}')

    return self
于 2018-10-11T13:25:09.433 回答
3

如果您正在构建的数据库中只有几个副本,我发现您可以使用管理界面中的后退按钮,更改必要的字段并再次保存实例。这对我有用,例如,我需要制作“gimlet”和“vodka gimlet”鸡尾酒,唯一的区别是替换名称和成分。显然,这需要对数据有一点预见性,并且不如覆盖 django 的复制/深度复制强大——但它可能对某些人有用。

于 2010-06-22T13:28:48.780 回答
3

Django 确实有一种通过管理员复制对象的内置方法 - 如此处回答: 在 Django 管理界面中,是否有方法复制项目?

于 2012-04-24T23:06:54.700 回答
2

简单的非通用方式

提出的解决方案对我不起作用,所以我采用了简单而不聪明的方法。这仅对简单的情况有用。

对于具有以下结构的模型

Book
 |__ CroppedFace
 |__ Photo
      |__ AwsReco
            |__ AwsLabel
            |__ AwsFace
                  |__ AwsEmotion

这行得通

def duplicate_book(book: Book, new_user: MyUser):
    # AwsEmotion, AwsFace, AwsLabel, AwsReco, Photo, CroppedFace, Book

    old_cropped_faces = book.croppedface_set.all()
    old_photos = book.photo_set.all()

    book.pk = None
    book.user = new_user
    book.save()

    for cf in old_cropped_faces:
        cf.pk = None
        cf.book = book
        cf.save()

    for photo in old_photos:
        photo.pk = None
        photo.book = book
        photo.save()

        if hasattr(photo, 'awsreco'):
            reco = photo.awsreco
            old_aws_labels = reco.awslabel_set.all()
            old_aws_faces = reco.awsface_set.all()
            reco.pk = None
            reco.photo = photo
            reco.save()

            for label in old_aws_labels:
                label.pk = None
                label.reco = reco
                label.save()

            for face in old_aws_faces:
                old_aws_emotions = face.awsemotion_set.all()
                face.pk = None
                face.reco = reco
                face.save()

                for emotion in old_aws_emotions:
                    emotion.pk = None
                    emotion.aws_face = face
                    emotion.save()
    return book
于 2017-02-24T17:50:53.180 回答
2

这是一个有点简单的解决方案。这不依赖于任何未记录的 Django API。它假定您要复制单个父记录,以及它的子记录、孙记录等。您传入一个实际上应该被复制的类的白名单,其形式是list指向其子对象的每个父对象上的一对多关系的名称。此代码假定,给定上述白名单,整个树是自包含的,无需担心外部引用。

author该解决方案对上述领域没有任何特殊作用。我不确定它是否适用。就像其他人所说的那样,该author字段可能不应该在不同的模型类中重复。

关于这段代码的另一件事:它是真正的递归,因为它为每个新级别的后代调用自己。

from collections import OrderedDict

def duplicate_model_with_descendants(obj, whitelist, _new_parent_pk=None):
    kwargs = {}
    children_to_clone = OrderedDict()
    for field in obj._meta.get_fields():
        if field.name == "id":
            pass
        elif field.one_to_many:
            if field.name in whitelist:
                these_children = list(getattr(obj, field.name).all())
                if children_to_clone.has_key(field.name):
                    children_to_clone[field.name] |= these_children
                else:
                    children_to_clone[field.name] = these_children
            else:
                pass
        elif field.many_to_one:
            if _new_parent_pk:
                kwargs[field.name + '_id'] = _new_parent_pk
        elif field.concrete:
            kwargs[field.name] = getattr(obj, field.name)
        else:
            pass
    new_instance = obj.__class__(**kwargs)
    new_instance.save()
    new_instance_pk = new_instance.pk
    for ky in children_to_clone.keys():
        child_collection = getattr(new_instance, ky)
        for child in children_to_clone[ky]:
            child_collection.add(duplicate_model_with_descendants(child, whitelist=whitelist, _new_parent_pk=new_instance_pk))
    return new_instance

示例用法:

from django.db import models

class Book(models.Model)
    author = models.ForeignKey('auth.User')

class Chapter(models.Model)
    # author = models.ForeignKey('auth.User')
    book = models.ForeignKey(Book, related_name='chapters')

class Page(models.Model)
    # author = models.ForeignKey('auth.User')
    # book = models.ForeignKey(Book)
    chapter = models.ForeignKey(Chapter, related_name='pages')

WHITELIST = ['books', 'chapters', 'pages']
original_record = models.Book.objects.get(pk=1)
duplicate_record = duplicate_model_with_descendants(original_record, WHITELIST)
于 2019-04-11T18:39:02.657 回答
1

我认为你也会更喜欢更简单的数据模型。

一个页面在某个章节中,但在另一本书中,这真的是真的吗?

userMe = User( username="me" )
userYou= User( username="you" )
bookMyA = Book( userMe )
bookYourB = Book( userYou )

chapterA1 = Chapter( book= bookMyA, author=userYou ) # "me" owns the Book, "you" owns the chapter?

chapterB2 = Chapter( book= bookYourB, author=userMe ) # "you" owns the book, "me" owns the chapter?

page1 = Page( book= bookMyA, chapter= chapterB2, author=userMe ) # Book and Author aggree, chapter doesn't?

看起来你的模型太复杂了。

我想你会更喜欢更简单的东西。我只是在猜测,因为我不知道你的整个问题。

class Book(models.Model)
    name = models.CharField(...)

class Chapter(models.Model)
    name = models.CharField(...)
    book = models.ForeignKey(Book)

class Page(models.Model)
    author = models.ForeignKey('auth.User')
    chapter = models.ForeignKey(Chapter)

每个页面都有不同的作者。然后,每一章都有作者的集合,这本书也是如此。现在您可以复制书籍、章节和页面,将克隆的页面分配给新作者。

实际上,您可能希望在 Page 和 Chapter 之间建立多对多关系,允许您仅拥有 Page 的多个副本,而无需克隆书籍和 Chapter。

于 2009-01-12T23:19:07.437 回答
1

我对Django 2.1.2的任何答案都没有运气,因此我创建了一种通用方法来执行数据库模型的深层副本,该模型很大程度上基于上面发布的答案。

与上述答案的主要区别在于ForeignKey不再具有名为 的属性rel,因此必须将其更改为f.remote_field.modeletc。

此外,由于很难知道应该复制数据库模型的顺序,我创建了一个简单的排队系统,如果当前模型复制不成功,则将其推到列表的末尾。代码如下:

import queue
from django.contrib.admin.utils import NestedObjects
from django.db.models.fields.related import ForeignKey

def duplicate(obj, field=None, value=None, max_retries=5):
    # Use the Nested Objects collector to retrieve the related models
    collector = NestedObjects(using='default')
    collector.collect([obj])
    related_models = list(collector.data.keys())

    # Create an object to map old primary keys to new ones
    data_snapshot = {}
    model_queue = queue.Queue()
    for key in related_models:
        data_snapshot.update(
            {key: {item.pk: None for item in collector.data[key]}}
        )
        model_queue.put(key)

    # For each of the models in related models copy their instances
    root_obj = None
    attempt_count = 0
    while not model_queue.empty():
        model = model_queue.get()
        root_obj, success = copy_instances(model, related_models, collector, data_snapshot, root_obj)

        # If the copy is not a success, it probably means that not
        # all the related fields for the model has been copied yet.
        # The current model is therefore pushed to the end of the list to be copied last
        if not success:

            # If the last model is unsuccessful or the number of max retries is reached, raise an error
            if model_queue.empty() or attempt_count > max_retries:
                raise DuplicationError(model)
            model_queue.put(model)
            attempt_count += 1
    return root_obj

def copy_instances(model, related_models, collector, data_snapshot, root_obj):

# Store all foreign keys for the model in a list
fks = []
for f in model._meta.fields:
    if isinstance(f, ForeignKey) and f.remote_field.model in related_models:
        fks.append(f)

# Iterate over the instances of the model
for obj in collector.data[model]:

    # For each of the models foreign keys check if the related object has been copied
    # and if so, assign its personal key to the current objects related field
    for fk in fks:
        pk_field = f"{fk.name}_id"
        fk_value = getattr(obj, pk_field)

        # Fetch the dictionary containing the old ids
        fk_rel_to = data_snapshot[fk.remote_field.model]

        # If the value exists and is in the dictionary assign it to the object
        if fk_value is not None and fk_value in fk_rel_to:
            dupe_pk = fk_rel_to[fk_value]

            # If the desired pk is none it means that the related object has not been copied yet
            # so the function returns unsuccessful
            if dupe_pk is None:
                return root_obj, False

            setattr(obj, pk_field, dupe_pk)

    # Store the old pk and save the object without an id to create a shallow copy of the object
    old_pk = obj.id
    obj.id = None

    if field is not None:
        setattr(obj, field, value)

    obj.save()

    # Store the new id in the data snapshot object for potential use on later objects
    data_snapshot[model][old_pk] = obj.id

    if root_obj is None:
        root_obj = obj

return root_obj, True

我希望它有任何帮助:)

重复错误只是一个简单的异常扩展:

class DuplicationError(Exception):
    """
    Is raised when a duplication operation did not succeed

    Attributes:
        model -- The database model that failed
    """

    def __init__(self, model):
        self.error_model = model

    def __str__(self):
        return f'Was not able to duplicate database objects for model {self.error_model}'
于 2018-11-15T17:38:15.163 回答
1

有一个选项可以在 django admin 中创建一个副本/克隆/另存为新。

  1. 在 admin.py 中创建要克隆的模型的 ModelAdmin 类
  2. 在类中添加一个管理操作,例如:
 @admin.register(Book)
 class BookAdmin(models.ModelAdmin):
     save_as = True

这将在您的管理面板中创建一个“另存为新”按钮,以完全克隆模型对象及其所有相关字段。

于 2019-12-06T08:03:30.717 回答
0

我尝试了 Stephen G Tuggy 的解决方案,发现它非常聪明,但不幸的是,它在某些特殊情况下不起作用。

让我们假设以下场景:

class FattAqp(models.Model):    
    descr = models.CharField('descrizione', max_length=200)
    ef = models.ForeignKey(Esercizio, ...)
    forn = models.ForeignKey(Fornitore, ...)

class Periodo(models.Model):
    #  id usato per identificare i documenti
    # periodo rilevato in fattura
    data_i_p = models.DateField('data inizio', blank=True)
    idfatt = models.ForeignKey(FattAqp, related_name='periodo')

class Lettura(models.Model):
    mc_i = models.DecimalField(max_digits=7, ...)
    faqp = models.ForeignKey(FattAqp, related_name='lettura')
    an_im = models.ForeignKey('cnd.AnagImm', ..)

class DettFAqp(models.Model):
    imponibile = models.DecimalField(...)
    voce = models.ForeignKey(VoceAqp, ...)
    periodo = models.ForeignKey(Periodo, related_name='dettfaqp')

在这种情况下,如果我们尝试对 FattAqp 实例进行深度复制,则 ef、forn、an_im 和 voce 字段将无法正确设置;另一方面,idfatt、faqp、periodo 将。

我通过向函数添加一个参数并对代码稍作修改来解决了这个问题。我用 Python 3.6 和 Django 2.2 对其进行了测试:

def duplicate_model_with_descendants(obj, whitelist, _new_parent_pk=None, static_fk=None):
    kwargs = {}
    children_to_clone = OrderedDict()
    for field in obj._meta.get_fields():
        if field.name == "id":
            pass
        elif field.one_to_many:
            if field.name in whitelist:
                these_children = list(getattr(obj, field.name).all())

                if field.name in children_to_clone:
                    children_to_clone[field.name] |= these_children
                else:
                    children_to_clone[field.name] = these_children
            else:
                pass
        elif field.many_to_one:
            name_with_id = field.name + '_id'
            if _new_parent_pk:
                kwargs[name_with_id] = _new_parent_pk

            if name_with_id in static_fk:
                kwargs[name_with_id] = getattr(obj, name_with_id)

        elif field.concrete:
            kwargs[field.name] = getattr(obj, field.name)
        else:
            pass
    new_instance = obj.__class__(**kwargs)
    new_instance.save()
    new_instance_pk = new_instance.pk
    for ky in children_to_clone.keys():
        child_collection = getattr(new_instance, ky)
        for child in children_to_clone[ky]:
            child_collection.add(
                duplicate_model_with_descendants(child, whitelist=whitelist, _new_parent_pk=new_instance_pk,static_fk=static_fk))

示例用法:

original_record = FattAqp.objects.get(pk=4)
WHITELIST = ['lettura', 'periodo', 'dettfaqp']
STATIC_FK = ['fornitore_id','ef_id','an_im_id', 'voce_id']
duplicate_record = duplicate_model_with_descendants(original_record, WHITELIST, static_fk=STATIC_FK)
于 2019-05-03T21:46:13.080 回答
0

根据以前的答案详细说明:

def derive(obj):
    import copy
    from django.contrib.admin.utils import NestedObjects
    from django.db import DEFAULT_DB_ALIAS
    from django.db.models.fields.related import ForeignKey
    """
        Derive a new model instance from previous one,
        and duplicate all related fields to point to the new instance
    """
    obj2 = copy.copy(obj)
    obj2.pk = None
    obj2.save()
    collector = NestedObjects(using=DEFAULT_DB_ALIAS)
    collector.collect([obj])
    collector.sort()
    related_models = collector.data.keys()
    data_snapshot = {}

    for key in collector.data.keys():
        data_snapshot.update({
            key: dict(
                zip(
                    [item.pk for item in collector.data[key]],
                    [item for item in collector.data[key]]
                )
            )
        })

    duplicate_order = reversed(related_models)

    for model in duplicate_order:
        # Find all FKs on model that point to a related_model.
        fks = []
        for f in model._meta.fields:
            if isinstance(f, ForeignKey) and f.rel.to in related_models:
                fks.append(f)
        # Replace each `sub_obj` with a duplicate.
        if model not in collector.data:
            continue
        sub_objects = collector.data[model]
        for obj in sub_objects:
            for fk in fks:
                dupe_obj = copy.copy(obj)
                setattr(dupe_obj, fk.name, obj2)
                dupe_obj.pk = None
                dupe_obj.save()
    return obj2
于 2019-08-15T19:48:01.357 回答
0

Julio Marins 的建议工作!谢谢!

对于 Django >= 2.* 这一行:

if isinstance(f, ForeignKey) and f.rel.to in related_models:

应替换为:

if isinstance(f, ForeignKey) and f.remote_field.model in related_models:

于 2020-01-17T08:14:27.823 回答