python - 用python计算的闪光距离

Question

定义闪光距离函数，它采用参数时间间隔（秒）并用公式计算：

the distance(in kilometers) = time interval(in seconds) * 330 / 1000.

以公里为单位的闪电距离并返回。距离应四舍五入为整数。返回值的闪光距离函数必须已经四舍五入。

我有这样的程序，但有些地方非常错误，我需要帮助。我必须做什么和怎么做？

def flash_distance (number_ms):
     flash_distance = (number_ms * 330/1000)
     round return (flash_distance * 330/1000)
   
distance_ms = 330

distance = int (input ("How many seconds it took seeing the lightning flash hearing?"))

print ("lightning distance in kilometers:" + str (flash_distance (distance_ms)))

Answer 1

我认为下面的代码将解决您的问题。在您的代码中，distance_ms已分配到 330，因此distance用户分配的变量将不起作用，这通常不是预期的。

def flash_distance (number_ms): 
     flash_distance = (number_ms * 330/1000)  
     return round (flash_distance)

distance_ms = int (input ("How many seconds it took seeing the lightning flash hearing?"))

print ("lightning distance in kilometers:" + str (flash_distance (distance_ms)))