1

运行 SQL 2008 R2。这个过程在 VS 2008 DB 项目中通过了验证，但在管理工作室中失败了。任何想法？

CREATE PROCEDURE [dbo].[WRHS_chkBinTransferItem]
(
 @BinFromID int,
 @BarCodeNumber varchar(50),
 @Count int,
 @Message varchar(500) OUTPUT
)

AS

DECLARE 
@LotTrackIND int,
@ItemID int,
@QtyAvail int,
@LotNumber varchar(50)

SELECT @ItemID = i.ItemID, @LotTrackIND = i.LotTrackingInd, @LotNumber = ''
FROM WRHS_ItemUOM iu
INNER JOIN WRHS_Item i ON iu.ItemID = i.ItemID
WHERE iu.BarcodeNumber = @BarCodeNumber
UNION
SELECT @ItemID = i.ItemID, @LotTrackIND = i.LotTrackingInd, @LotNumber = wil.LotNumber
FROM WRHS_WarehouseItemLotIdentify wili
INNER JOIN WRHS_WarehouseItemLot wil ON wili.WarehouseItemLotID = wil.WarehouseItemLotID
INNER JOIN WRHS_WarehouseItem wi ON wil.WarehouseItemID = wi.WarehouseItemID
INNER JOIN WRHS_Item i ON wi.ItemID = i.ItemID
WHERE wili.ItemIdentification = @BarCodeNumber

IF @LotTrackIND = 1
 BEGIN
  IF @ItemID > 0
   BEGIN
    SELECT DISTINCT @QtyAvail = q.Qty
    FROM WRHS_BinItem bi 
    INNER JOIN WRHS_BinItemQty q ON bi.BinItemID = q.BinItemID
    WHERE bi.BinID = @BinFromID AND bi.ItemID = @ItemID AND q.LotNumber = @LotNumber

    IF @Count <= @QtyAvail
     BEGIN
      SELECT DISTINCT q.BinItemQtyID, RTRIM(i.ItemNumber) as ItemNumber, i.LicensePlateInd, q.LotNumber, i.LotTrackingInd, i.ItemID, wi.ForcedPutAwayInd
      FROM WRHS_Bin b
      INNER JOIN WRHS_BinItem bi ON b.BinID = bi.BinID
      INNER JOIN WRHS_BinItemQty q ON bi.BinItemID = q.BinItemID
      INNER JOIN WRHS_Item i On bi.ItemID = i.ItemID
      INNER JOIN WRHS_WarehouseItem wi ON b.WarehouseID = wi.WarehouseID AND i.ItemID = wi.ItemID
      WHERE b.BinID = @BinFromID AND bi.ItemID = @ItemID AND q.LotNumber = @LotNumber

      SET @Message = 'Success'
     END
    ELSE
     BEGIN
      SET @Message = 'Selected Quantity not Available'
     END
   END
  ELSE
   BEGIN
    SET @Message = 'Invalid BarCode Scan, this Item is Lot Tracked and the proper BarCode must be scanned.'
   END
 END
ELSE
 BEGIN
  IF @ItemID > 0
   BEGIN
    SELECT DISTINCT @QtyAvail = q.Qty
    FROM WRHS_BinItem bi 
    INNER JOIN WRHS_BinItemQty q ON bi.BinItemID = q.BinItemID
    WHERE bi.BinID = @BinFromID AND bi.ItemID = @ItemID AND q.LotNumber = @LotNumber

    IF @Count <= @QtyAvail
     BEGIN
      SELECT DISTINCT q.BinItemQtyID, RTRIM(i.ItemNumber) as ItemNumber, i.LicensePlateInd, q.LotNumber, i.LotTrackingInd, i.ItemID, wi.ForcedPutAwayInd
      FROM WRHS_Bin b
      INNER JOIN WRHS_BinItem bi ON b.BinID = bi.BinID
      INNER JOIN WRHS_BinItemQty q ON bi.BinItemID = q.BinItemID 
      INNER JOIN WRHS_ItemUOM iu ON bi.ItemID = iu.ItemID
      INNER JOIN WRHS_Item i On bi.ItemID = i.ItemID
      INNER JOIN WRHS_WarehouseItem wi ON b.WarehouseID = wi.WarehouseID AND i.ItemID = wi.ItemID
      WHERE b.BinID = @BinFromID AND bi.ItemID = @ItemID AND q.LotNumber = @LotNumber

      SET @Message = 'Success'
     END
    ELSE
     BEGIN
      SET @Message = 'Selected Quantity not Available'
     END
   END
  ELSE
   BEGIN
    SET @Message = 'Invalid BarCode Scan'
   END
 END
4

3 回答 3

4

对于作业，部分，您可以在子查询的帮助下解决它，例如：

Select @ItemID = ItemID, @LotTrackIND = LotTrackingInd, @LotNumber = LotNumber
  from (
        SELECT i.ItemID, i.LotTrackingInd, '' LotNumber
        FROM WRHS_ItemUOM iu
        INNER JOIN WRHS_Item i ON iu.ItemID = i.ItemID
        WHERE iu.BarcodeNumber = @BarCodeNumber
        UNION
        SELECT i.ItemID, i.LotTrackingInd, wil.LotNumber
        FROM WRHS_WarehouseItemLotIdentify wili
        INNER JOIN WRHS_WarehouseItemLot wil ON wili.WarehouseItemLotID = wil.WarehouseItemLotID
        INNER JOIN WRHS_WarehouseItem wi ON wil.WarehouseItemID = wi.WarehouseItemID
        INNER JOIN WRHS_Item i ON wi.ItemID = i.ItemID
        WHERE wili.ItemIdentification = @BarCodeNumber
       ) q1

我警告您没有迭代您的查询可能返回的（可能的）多条记录。

此致。

于 2010-11-10T01:33:16.020 回答
0

是的，错误就在这部分，

SELECT @ItemID = i.ItemID, @LotTrackIND = i.LotTrackingInd, @LotNumber = '' 
FROM WRHS_ItemUOM iu 
INNER JOIN WRHS_Item i ON iu.ItemID = i.ItemID 
WHERE iu.BarcodeNumber = @BarCodeNumber 
UNION 
SELECT @ItemID = i.ItemID, @LotTrackIND = i.LotTrackingInd, @LotNumber = wil.LotNumber 
FROM WRHS_WarehouseItemLotIdentify wili 
INNER JOIN WRHS_WarehouseItemLot wil ON wili.WarehouseItemLotID = wil.WarehouseItemLotID 
INNER JOIN WRHS_WarehouseItem wi ON wil.WarehouseItemID = wi.WarehouseItemID 
INNER JOIN WRHS_Item i ON wi.ItemID = i.ItemID 
WHERE wili.ItemIdentification = @BarCodeNumber

如果语句具有 UNION，则不能使用 select 语句为变量赋值。如果你仔细想想，这没有任何意义。变量只能保存一个值，但它应该选择哪一个呢？第一个 select 语句中的那个还是第二个？

您必须明确做出该选择。假设您希望第二个 select 语句优先（即从第二个 select 中获取值。如果第二个 select 语句没有返回值，则取第一个返回的值），您可以执行以下操作

SELECT @ItemID = i.ItemID, @LotTrackIND = i.LotTrackingInd, @LotNumber = '' 
FROM WRHS_ItemUOM iu 
INNER JOIN WRHS_Item i ON iu.ItemID = i.ItemID 
WHERE iu.BarcodeNumber = @BarCodeNumber 

SELECT @ItemID = i.ItemID, @LotTrackIND = i.LotTrackingInd, @LotNumber = wil.LotNumber 
FROM WRHS_WarehouseItemLotIdentify wili 
INNER JOIN WRHS_WarehouseItemLot wil ON wili.WarehouseItemLotID = wil.WarehouseItemLotID 
INNER JOIN WRHS_WarehouseItem wi ON wil.WarehouseItemID = wi.WarehouseItemID 
INNER JOIN WRHS_Item i ON wi.ItemID = i.ItemID 
WHERE wili.ItemIdentification = @BarCodeNumber
于 2010-11-10T00:11:41.077 回答
0

在你的工会中你不能做变量赋值

SELECT @ItemID = i.ItemID, @LotTrackIND = i.LotTrackingInd, @LotNumber = ''  
...
UNION
SELECT @ItemID = i.ItemID, @LotTrackIND = i.LotTrackingInd, @LotNumber = wil.LotNumber 
...

正如错误所说。

至于为什么它在VS中通过，这是一个VS错误。

于 2010-11-10T00:08:13.767 回答