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我有一个 ios 应用程序和一个 Web 应用程序,它们从用户那里获得授权并生成一个 authcode 并将其发送到后端 java servlet,后者试图交换 authcode 以获取访问和刷新令牌。从 Web 应用程序交换身份验证码正在工作,但对于从 ios 应用程序生成的身份验证码,我在交换过程中收到以下错误。

com.google.api.client.auth.oauth2.TokenResponseException: 400 Bad Request { "error" : "invalid_request", "error_description" : "Missing parameter: redirect_uri" }

这是进行交换的代码

      public OAuthCodeExchangeResponse exchangeAuthCode(String authCode, boolean isIosApp) throws JSONException, IOException {
OAuthCodeExchangeResponse response = new OAuthCodeExchangeResponse();
GoogleClientSecrets clientSecrets = getClientSecrets(isIosApp);
// Build flow and trigger user authorization request.
GoogleAuthorizationCodeFlow flow =
    new GoogleAuthorizationCodeFlow.Builder(
        HTTP_TRANSPORT, JSON_FACTORY, clientSecrets, SCOPES)
        .setAccessType("offline")
        .build();
GoogleTokenResponse tokenResponse = null;
if(isIosApp == false) {
  tokenResponse = flow.newTokenRequest(authCode)
      .setRedirectUri("postmessage")
      .execute();
} else {
  tokenResponse = flow.newTokenRequest(authCode).execute();
}
GoogleIdToken idToken = tokenResponse.parseIdToken();
GoogleIdToken.Payload payload = idToken.getPayload();
response.setAccessToken(tokenResponse.getAccessToken());
response.setEmail(payload.getEmail());
response.setIdToken(tokenResponse.getIdToken());
response.setRefreshToken(tokenResponse.getRefreshToken());
return response;
}

public GoogleClientSecrets getClientSecrets(boolean isIosApp) throws JSONException, IOException {
GoogleClientSecrets.Details d = new GoogleClientSecrets.Details();
if(isIosApp == false) {
  d.setClientId(WebClientId);
  d.setClientSecret(WebClientSecret);
} else {
  d.setClientId(PhoneClientId);
}
GoogleClientSecrets clientSecrets = new GoogleClientSecrets();
clientSecrets.setInstalled(d);
return clientSecrets;
}

交换从 ios 应用程序生成的 authcode 时,我必须设置什么 redirect_uri?顺便说一句,在谷歌开发者控制台中为 ios 应用程序创建的凭据没有重定向 uri 集。

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1 回答 1

0

瓮:ietf:wg:oauth:2.0:oob

您需要已安装应用程序的流程,请参阅https://developers.google.com/identity/protocols/OAuth2InstalledApp#formingtheurl

于 2016-05-27T21:18:50.000 回答