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我使用Jabber.NET连接到OpenFire服务器。客户有时（但大多数时候）给我一个奇怪的异常： jabber.connection.sasl.SASLException: Hash ist im angegebenen Status nicht gültig，这是一条德语消息，指出哈希对于指定状态无效。有时（是的，我知道，但我不能影响）它，我也会得到 Exception jabber.connection.sasl.SASLException: Das SafeHandle wurde geschlossen，这意味着 SafeHandle 已关闭。

我尝试关闭所有可能的安全设置，但这一切都没有效果。这就是我的连接方式：

    private JabberClient _jabberClient = null;
    public JabberClient XmppClient
    {
        get
        {
            if (_jabberClient == null)
                _jabberClient = new JabberClient();
            return _jabberClient;
        }
    }

    // double checked: username and password are correct, servername is existing URL
    public login(username,password,servername)
    {
        var jid = new JID(username, serverName, Guid.NewGuid().ToString());
        bedrock.net.AsyncSocket.UntrustedRootOK = true;
        XmppClient.RequiresSASL = false; // --> this seems to have no effect at all
        //XmppClient[Options.SASL_MECHANISMS] = MechanismType.PLAIN; // setting this throws a NotImplementedException!!!
        XmppClient.SSL = false;
        XmppClient.AutoPresence = true;
        XmppClient.AutoReconnect = 3.0f;
        XmppClient.AutoLogin = true;
        XmppClient.AutoStartTLS = true;
        XmppClient.AutoStartCompression = false;
        XmppClient.User = jid.User;
        XmppClient.Password = password;
        XmppClient.Resource = jid.Resource;
        XmppClient.Server = serverName;
        XmppClient.NetworkHost = serverName;

        XmppClient.OnMessage += new MessageHandler(JabberClient_OnMessage);
        XmppClient.OnDisconnect += new bedrock.ObjectHandler(JabberClient_OnDisconnect);
        XmppClient.OnError += new bedrock.ExceptionHandler(JabberClient_OnError);
        XmppClient.OnAuthError += new jabber.protocol.ProtocolHandler(JabberClient_OnAuthError);
        XmppClient.OnAuthenticate += new bedrock.ObjectHandler(XmppClient_OnAuthenticate);
        XmppClient.OnInvalidCertificate += new System.Net.Security.RemoteCertificateValidationCallback(XmppClient_OnInvalidCertificate);
        XmppClient.OnWriteText += new bedrock.TextHandler(XmppClient_OnWriteText);
    }

我该如何解决这个问题？什么可以规避它？我现在唯一的可能性是验证很多次，直到它幸运地工作，但这可能需要一些时间，我不想诉诸于此。

编辑：下面的答案让我得到了答案：它就像识别异常并connect()再次调用一样简单。为什么图书馆不自动执行此操作对我来说是个谜，我也不明白为什么它在停用时使用 SASL，但是很好。被黑了，有效。谢谢！

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1 回答 1

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我没有看到问题，但这是我的工作代码。希望能帮助到你。

    private JabberClient _client;
    private JabberClient client
    {
        get {
            if (_client == null)
            {
                _client = new JabberClient();
                ConfigureClient(_client);
            }
            return _client; 
        }
        set
        {
            _client = value;
            RegisterOnEvents(_client);
        }
    }      

    public MiddleMan()
    {
        jabber.connection.ConferenceManager c = new jabber.connection.ConferenceManager();

        client = new JabberClient();

        ConfigureClient(client);
    }  

    private void ConfigureClient(JabberClient jc)
    {
        JID jid = new JID(LoginInformation.UserName);

        jc.User = jid.User;
        jc.Server = jid.Server;
        if (!String.IsNullOrEmpty(LoginInformation.NetworkHost))
        {
            jc.NetworkHost = LoginInformation.NetworkHost;
        }
        jc.Port = 5222;
        jc.AutoReconnect = 3f;
        jc.AutoLogin = true;
        jc.AutoPresence = true;
        jc.Resource = LoginInformation.Resource;
        jc.Password = LoginInformation.Password;
        jc.KeepAlive = 10;
    }

    private void RegisterOnEvents(JabberClient jc)
    {
        //Messaging
        //jc.OnMessage += new MessageHandler(OnMessageReceived);

        //Login
        jc.OnLoginRequired += (sender) =>
        {
           //code
        };

        jc.OnAuthenticate += (sender) =>
        {
            //code
        };

        jc.OnAuthError += (sender, rp) =>
        {
            //code
            this.Connect();
        };

        //Connection
        jc.OnConnect += (sender, stream) =>
        {
            //code
        };

        jc.OnDisconnect += (sender) =>
        {
            //code
            this.Connect();
        };

        jc.OnError += (sender, ex) =>
        {
            //code
            this.Connect();
        };

        //jc.OnPresence += new PresenceHandler(OnPresence);
    }
于 2012-10-22T08:46:49.397 回答