假设您的四个矩阵数据分别存储在 data/a.txt、data/b.txt、data/c.txt、data/d.txt 中,以下代码将产生所需的结果。
arma::mat a,b,c,d ;
a.load("data/a.txt");
b.load("data/b.txt");
c.load("data/c.txt");
d.load("data/d.txt");
// join rows (=horizontally, i.e. matrices must have the same number of rows)
auto joined_ab = std::move(arma::join_rows( a, b ));
auto joined_cd = std::move(arma::join_rows( c, d ));
// join columns (=vertically, i.e. matrices must have the same number of cols)
auto joined_mat = std::move(arma::join_cols( joined_ab, joined_cd ));
std::cout << joined_mat << std::endl;
注意:对于原始问题,以下成立;
a = 矩阵 0
b = 矩阵 1
c = 矩阵 2
d = 矩阵 3
所以上面的构造产生:
a | b
--+---
c | d