iphone - 如何获取 UIView 的访问子视图？

Question

根据此代码，如果我想访问 imageView1 和 imageView2 我该如何访问它？请给我看一些例子

例如 cell.accessoryView.subviews ？

UIImageView *imageView1 = [[[UIImageView alloc] init] autorelease];
UIImageView *imageView2 = [[[UIImageView alloc] init] autorelease];
imageView2.alpha = 0;
[cell.accessoryView addSubview:imageView1];
[cell.accessoryView addSubview:imageView2];

Answer 1

You can use view's tag property:

UIImageView *imageView1 = [[[UIImageView alloc] init] autorelease];
imageView1.tag = 100;
UIImageView *imageView2 = [[[UIImageView alloc] init] autorelease];
imageView2.tag = 200;
imageView2.alpha = 0;
[cell.accessoryView addSubview:imageView1];
[cell.accessoryView addSubview:imageView2];

And later get subview using -viewWithTag: method:

UIImageView *getImageView1 = (UIImageView*)[cell.accessoryView viewWithTag:100];

Answer 2

I believe u can access all subviews in superview simply by calling
[cell.accessoryView subviews].