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given the line y=(-8/5)x-(4/5) or 8x+5y-4 find the equation of a line that is 6 units away from the given line. I've tried looking how to solve this problem with no luck, I have a feeling I need to use the distance between a line and a point formula and the distannce formula i just can figure out how.

Distance formula= sqrt((x1-x2)^2+(y1-y2)^2) this should equal 6

Distance between a line and a point= ((|Ax+By+C|)/sqrt(A^2+B^2)) this should also equal 6

what I tried doing was pluggin in the numbers and setting both of the equations equal to each other and solving for the x and y. With that I can easily fin the equation of the line.

Any suggestions on how to do this??

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1 回答 1

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如果这条线被描述为 y = ax + b，并且你想要一条距离为 d 的平行线，那么这条线的公式是 y = ax +b ± kd，其中 k = sqrt(a 2 +1)。

至于为什么，您对向量感到满意吗？

于 2014-03-02T05:54:20.700 回答