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我正在尝试使用 Breeze 线性代数包 ( https://github.com/scalanlp/breeze ) 和我自己的代表 GF2 字段的数据类型来实现 Humming 编码。到目前为止,我已经成功地实现了我的 GF2:

package humming

trait GF2 {
  def + (that: GF2): GF2
  def * (that: GF2): GF2

  def / (that: GF2) = that match {
    case Zero => throw new IllegalArgumentException("Div by 0")
    case _ => this
  }
}

object Zero extends GF2 {
  override def toString = "Zero"
  def + (that: GF2) = that
  def * (that: GF2) = this
}

object One extends GF2 {
  override def toString = "One"
  def + (that: GF2) = that match { case One => Zero ; case _ => this }
  def * (that: GF2) = that match { case One => this ; case _ => that }
}

以及创建 GF2 值矩阵所需的类型类:

import breeze.linalg._
import breeze.numerics._
import breeze.storage._
import scala.reflect._
import breeze.math._
import humming._

implicit object GF2DefaultArrayValue extends DefaultArrayValue[GF2] {
  override def value = Zero
}

implicit object GF2Semiring extends Semiring[GF2] {
  def defaultArrayValue = GF2DefaultArrayValue
  def manifest = classTag[GF2]
  def zero = Zero
  def one = One

  def ==(a: GF2, b: GF2) = a == b
  def !=(a: GF2, b: GF2) = a != b
  def +(a: GF2, b: GF2) = a + b
  def *(a: GF2, b: GF2) = a * b
}

val a = DenseMatrix.eye[GF2](5)

但是当我尝试将矩阵添加到自身时,我收到以下错误:

a + a  
// could not find implicit value for parameter op:  
// breeze.linalg.operators.BinaryOp[breeze.linalg.DenseMatrix[humming.GF2],  
// breeze.linalg.DenseMatrix[humming.GF2],breeze.linalg.operators.OpAdd,That]

在这一点上,我被困住了,因为我不太明白我现在应该实现什么类型的类。看着breeze.linalg.operators并没有多大帮助。所以问题是我应该怎么做才能将我的 GF2 与 Breeze 结合起来,以支持所有矩阵/向量运算?

==============
0.6版解决了上面的问题
但是,我仍然无法将矩阵乘以向量或乘以值:

val a = DenseMatrix.eye[GF2](5)
val b = DenseVector.ones[GF2](5)
a + a // OK

a * b  
// Could not find an implicit implementation for this UFunc with arguments  
// breeze.linalg.DenseMatrix[humming.GF2], breeze.linalg.DenseVector[humming.GF2]

a + One  
// Could not find an implicit implementation for this UFunc with arguments  
// breeze.linalg.DenseMatrix[humming.GF2], humming.One.type

我想我必须提供一个UFunc实现。它应该是什么样子?

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1 回答 1

4

这适用于 Breeze 的最新快照。我将在本周末发布 0.6。

scala> val a = DenseMatrix.eye[GF2](5)
a: breeze.linalg.DenseMatrix[X.GF2] =
One   Zero  Zero  Zero  Zero
Zero  One   Zero  Zero  Zero
Zero  Zero  One   Zero  Zero
Zero  Zero  Zero  One   Zero
Zero  Zero  Zero  Zero  One

scala> a + a
res0: breeze.linalg.DenseMatrix[X.GF2] =
Zero  Zero  Zero  Zero  Zero
Zero  Zero  Zero  Zero  Zero
Zero  Zero  Zero  Zero  Zero
Zero  Zero  Zero  Zero  Zero
Zero  Zero  Zero  Zero  Zero
于 2014-02-15T17:27:02.537 回答