1

伙计们，

如果您将 2 个数据框 df1 和 df2 连接或合并，我想连接或合并。我的目标很简单，就像创建一个新数据框，其列是 df1 和 df2 的并集。

例子

product=c("p1","p1","p1","p1","p1","p1","p1","p1","p2","p2","p2","p2","p2","p2","p2","p2","p3","p3","p3","p3","p3","p3","p3","p3","p4","p4","p4","p4","p4","p4","p4","p4")
skew=c("b","b","b","b","a","a","a","a","b","b","b","b","a","a","a","a","b","b","b","b","a","a","a","a","b","b","b","b","a","a","a","a")
version=c(0.1,0.1,0.2,0.2,0.1,0.1,0.2,0.2,0.1,0.1,0.2,0.2,0.1,0.1,0.2,0.2,0.1,0.1,0.2,0.2,0.1,0.1,0.2,0.2,0.1,0.1,0.2,0.2,0.1,0.1,0.2,0.2)
color=c("C1","C2","C1","C2","C1","C2","C1","C2","C1","C2","C1","C2","C1","C2","C1","C2","C1","C2","C1","C2","C1","C2","C1","C2","C1","C2","C1","C2","C1","C2","C1","C2")
price=c(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32)

df1 = data.frame(product, skew, version)
df2 = data.frame(product, skew, color, price)

我的愿望是得到如下结果。

我尝试了几个选项：

#option 1 with cbind
df <- cbind(df1,df2)

这将返回一个数据框重复列“product”和“skew”。

# Option 2, use data.frame
df <- data.frame(df1,df2)

这给了我几乎想要的东西，除了它有额外的“产品”和“倾斜”列。它们的后缀是“.1”，所以没有重复。

# option 3, use merge which seems to be the way to go
df <- merge(df1,df2)

我认为我在合并时遗漏了一些东西，因为这实际上从所有数据集中创建了一个联合，在提供的 32 个观察值中总共产生了 128 个观察值。我想这就是合并的工作原理。我已经运行了“？合并”并尝试了一些选项，但无法让它吐出我想要的东西。

所以我的问题是：

如上所述从 df1 和 df2 中获取所需数据帧的最佳方法是什么？

提前感谢您的帮助！里亚德。

     product skew  version color price
1       p1    b     0.1    C1     1
2       p1    b     0.1    C2     2
3       p1    b     0.2    C1     3
4       p1    b     0.2    C2     4
5       p1    a     0.1    C1     5
6       p1    a     0.1    C2     6
7       p1    a     0.2    C1     7
8       p1    a     0.2    C2     8
9       p2    b     0.1    C1     9
10      p2    b     0.1    C2    10
11      p2    b     0.2    C1    11
12      p2    b     0.2    C2    12
13      p2    a     0.1    C1    13
14      p2    a     0.1    C2    14
15      p2    a     0.2    C1    15
16      p2    a     0.2    C2    16
17      p3    b     0.1    C1    17
18      p3    b     0.1    C2    18
19      p3    b     0.2    C1    19
20      p3    b     0.2    C2    20
21      p3    a     0.1    C1    21
22      p3    a     0.1    C2    22
23      p3    a     0.2    C1    23
24      p3    a     0.2    C2    24
25      p4    b     0.1    C1    25
26      p4    b     0.1    C2    26
27      p4    b     0.2    C1    27
28      p4    b     0.2    C2    28
29      p4    a     0.1    C1    29
30      p4    a     0.1    C2    30
31      p4    a     0.2    C1    31
32      p4    a     0.2    C2    32
4

2 回答 2

2

您可以使用union()，但它会弄乱列名。

df_c <- union(df1, df2)
names(df_c) <- union(names(df1), names(df2))
df_c <- as.data.frame(df_c)
于 2013-12-03T07:14:58.403 回答
1

merge() 无法按您希望的方式工作，因为您的列“product”和“skew”不是唯一标识符。组合出现多次。因此 merge() 计算每个可能的组合。您可以包含第三列作为 id：

product=c("p1","p1","p1","p1","p1","p1","p1","p1","p2","p2","p2","p2","p2","p2","p2","p2","p3","p3","p3","p3","p3","p3","p3","p3","p4","p4","p4","p4","p4","p4","p4","p4")
skew=c("b","b","b","b","a","a","a","a","b","b","b","b","a","a","a","a","b","b","b","b","a","a","a","a","b","b","b","b","a","a","a","a")
version=c(0.1,0.1,0.2,0.2,0.1,0.1,0.2,0.2,0.1,0.1,0.2,0.2,0.1,0.1,0.2,0.2,0.1,0.1,0.2,0.2,0.1,0.1,0.2,0.2,0.1,0.1,0.2,0.2,0.1,0.1,0.2,0.2)
color=c("C1","C2","C1","C2","C1","C2","C1","C2","C1","C2","C1","C2","C1","C2","C1","C2","C1","C2","C1","C2","C1","C2","C1","C2","C1","C2","C1","C2","C1","C2","C1","C2")
price=c(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32)
id = 1:32

df1 = data.frame(product, skew, id, version)
df2 = data.frame(product, skew, id, color, price)
merge(df1, df2)

或者您手动合并您的 data.frames：

cbind(df1, df2[, 3:4])
于 2013-12-03T07:12:34.300 回答