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我正在做Person-Environment fit研究，并希望在Lattice线框绘制的响应面的xy平面上添加P = E和P = -E线。目前，我得到的代码如下：

PersonIV <- seq(-3, 3, length = 30)
EnvironmentIV <- seq(-3, 3, length = 30)
g.test.data <- expand.grid(PersonIV = PersonIV, EnvironmentIV = EnvironmentIV)
g.test.data$DV <- .5 + .4 * PersonIV + .6 * EnvironmentIV + .9 * PersonIV^2 + .7 * PersonIV * EnvironmentIV - .3 * EnvironmentIV^2

library(lattice)
trellis.par.set("axis.line", list(col = NA))
wireframe(DV ~ PersonIV * EnvironmentIV, g.test.data, 
          drape = T, screen = list(z = 30, x = -75), 
          main = "Person - Environment Fit Response Surface", 
          xlab = list(xlim = c(-3:3), label = "Personal IV", col = "black", font = 1, cex = 1, rot = 15), 
          ylab = list(label = "Environment IV", ylim = c(-3: 3), font = 1, cex = 1, rot = -42), 
          zlab = list(label = "DV", zlim = c(0:5), font = 1, cex = 1, rot = 90, lines = T), 
          scale = list(arrows = F, cex = 1, col = "black", tck = 1), 
          par.settings = list(box.3d = list(col=c(1,1,NA,NA,1,NA,1,1,1))), 

          )

非常感谢！

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1 回答 1

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制作自定义面板函数并将其传递给wireframe带有panel参数的格子绘图函数（此处为 ）是执行此操作的常用方法。重新创建现有的情节，panel.xyplot通常使用，并添加线条，panel.abline通常使用。也许是这样的。

panel=function(...) {panel.xyplot(...); panel.abline(0,1); panel.abline(0,-1)}
于 2013-12-03T02:06:06.243 回答