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我遇到了 UrlDisplay 不显示任何数据的问题。UrlDisplay 位于我的.M 的底部。我正在做的是请求一个网站收集一些特定于用户请求的 url。然后为他们设置 UiWebViews 进行导航，但有什么方法可以拆分单个 UiWebView，或者这是最好的方法吗？（我的示例仅收集一个网站并尝试将一个网站设置为 UIWebView）我不确定为什么会发生这种情况 .h 中的所有内容都正确连接到情节提要。感谢您提供任何反馈的高级帮助！

。H

#import <UIKit/UIKit.h>

@interface ViewController : UIViewController
@property (weak, nonatomic) IBOutlet UIWebView *UrlDisplay;

@end

.M

#import "ViewController.h"

@interface ViewController ()

@end

@implementation ViewController

@synthesize UrlDisplay;

- (void)viewDidLoad
{
[super viewDidLoad];


NSURL *website = [NSURL URLWithString:@"www.Google.com"];



NSURLRequest *request = [NSURLRequest requestWithURL:website];



NSURLResponse* response = nil;

NSError *error = nil;

NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];

//storing data in a string

NSString *myString = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];

NSArray *newString = [myString componentsSeparatedByString:@"\n"];
// Do any additional setup after loading the view, typically from a nib.

NSMutableString *curLineNum;

NSString *curLine;

NSMutableArray *URL =[[NSMutableArray alloc]init];

int i;

for (i = 0; i <[newString count]; i++) {

    curLine = [newString objectAtIndex:i];

    if ([curLine rangeOfString:@"Start Here"].location != NSNotFound) {

        NSScanner *scanner = [NSScanner scannerWithString:curLine];

        [scanner scanUpToString:@"Start Here" intoString:NULL];

        [scanner setScanLocation:([scanner scanLocation]) + 16];

        [scanner scanUpToString:@"End Here" intoString:&curLineNum];

        [Url addObject:curLineNum];


    }
}

NSURL *preWebsite = [NSURL URLWithString:[Url objectAtIndex:0]];

NSURLRequest *preRequest = [NSURLRequest requestWithURL:preWebsite];

[UrlDisplay loadRequest:preRequest];
//NSLog(@"%@",myString);

}

- (void)didReceiveMemoryWarning
{
[super didReceiveMemoryWarning];
// Dispose of any resources that can be recreated.
}

@end
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1 回答 1

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URLWithString 方法总是需要完整的 URL 路径，包括 URL 方案。在您的情况下，缺少 URL 方案。尝试这个。 

NSURL *website = [NSURL URLWithString:@"http://www.Google.com"];
于 2013-10-16T20:11:36.983 回答