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We currently have a script that generates random passwords and we utilize another function to read from this password list for various tasks. While using these passwords they are passed into a variable let's call $password. So,

$password = FindPassword "blah"

If I were to print $password then it would return say, Q@48$$!y@&$^

The issue with this, is when I replace a word in a file using $password it is missing one of the $ so, Q@48$!y@&$^

Here is the code I am using for the replace,

(Get-Content $Some_File) |
    Foreach-Object {$_ -replace "PASSWORD","${Password}"} | Set-Content $Some_File

Anyone know of a way to show two $$ in a row? I have tried using something like this to ensure special characters are treated appropriately, but can't get the $ to work:

$password = $password.Replace("`^","`^")
$password = $password.Replace("`@","`@")
$password = $password.Replace("`&","`&")
$password = $password.Replace("`!","`!")
$password = $password.Replace("\`$","\`$")

Also,

$password = $password.Replace("`$","``$")

Will work, but if the password is different the next time around, it is only unique to this particular example.

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1 回答 1

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如果你用方法替换-replace操作符.replace()，它就可以了：

(Get-Content $Some_File) |
    Foreach-Object { $_.toString().Replace("PASSWORD", $password.ToString()) } | Set-Content $Some_File
于 2013-10-07T16:56:44.103 回答