我有一个包含时间（分钟和秒）的文件，大致如下：
02:53 rest of line 1...
03:10 rest of line 2...
05:34 rest of line 3...
05:35 rest of line 4...
10:02 rest of line 5...
...
我想以秒为单位替换时间。理想情况下，我想运行一些像这样的神奇命令：
:%s/^\(\d\d\):\(\d\d\) \(.*\)/(=\1*60 + \2) \3/g
...(=\1*60 + \2)神奇的部分在哪里。我知道我可以使用特殊寄存器插入评估结果=，但是有没有办法在正则表达式的 subst 部分执行此操作？
像这样的东西？
:%s/^\(\d\d\):\(\d\d\)/\=submatch(1)*60+submatch(2)/
当替换以 a 开头时，替换\=被解释为表达式。
:h sub-replace-expression在下面复制
Substitute with an expression *sub-replace-expression*
*sub-replace-\=*
When the substitute string starts with "\=" the remainder is interpreted as an
expression. This does not work recursively: a substitute() function inside
the expression cannot use "\=" for the substitute string.
The special meaning for characters as mentioned at |sub-replace-special| does
not apply except for "<CR>", "\<CR>" and "\\". Thus in the result of the
expression you need to use two backslashes to get one, put a backslash before a
<CR> you want to insert, and use a <CR> without a backslash where you want to
break the line.
For convenience a <NL> character is also used as a line break. Prepend a
backslash to get a real <NL> character (which will be a NUL in the file).
When the result is a |List| then the items are joined with separating line
breaks. Thus each item becomes a line, except that they can contain line
breaks themselves.
The whole matched text can be accessed with "submatch(0)". The text matched
with the first pair of () with "submatch(1)". Likewise for further
sub-matches in ().
用于submatch()指代替换位置中的分组部分：
:%s/\v^(\d{2}):(\d{2})>/\=submatch(1) * 60 + submatch(2)/
用你的例子产生：
173 rest of line 1...
190 rest of line 2...
334 rest of line 3...
335 rest of line 4...
602 rest of line 5...
希望它对其他人有帮助，但我有类似的问题，我想用不同的数字替换“id”，实际上是任何其他数字
{"id":1,"first_name":"Ruperto","last_name":"Bonifayipio","gender":"Male","ssn":"318-69-4987"},
用过的表达
%s/\v(\d+),/\=submatch(1)*1111/g
这导致以下新值
{"id":1111,"first_name":"Ruperto","last_name":"Bonifayipio","gender":"Male","ssn":"318-69-4987"},