0

我想要做的是让我的程序在更改图像之前等待 3 秒。我做了我的研究，似乎这可以解决它，但它告诉我我需要使 c1 和 c2 成为最终的。但是，这将破坏我的其余代码。

我试图在 3 秒后运行这两行：

c1.getImg().setImageResource(R.drawable.facedown);
c2.getImg().setImageResource(R.drawable.facedown);

有什么解决方案？谢谢！

private Thread thread;

public void checkMatch(int num) {
    flips++;
    President c1 = null;
    President c2 = cards.get(num - 1);
    if (flips % 2 != 0) {
        return;
    } else {
        for (President c : cards) {
            if (c.isFlipped() == true && c.isMatched() == false && c != c2) {
                c1 = c;
            }
        }

        if (c1.getPresident() == c2.getPresident()) {
            cards.get(c1.getCard() - 1).setMatched(true);
            cards.get(c2.getCard() - 1).setMatched(true);
        } else {

            cards.get(c1.getCard() - 1).setFlipped(false);
            cards.get(c2.getCard() - 1).setFlipped(false);

             thread = new Thread() {
             @Override
             public void run() {
             try {
             synchronized (this) {
             wait(3000);
             }
             } catch (InterruptedException ex) {
             }

             // TODO
//THESE TWO LINES ARE THE ONES I WANT TO RUN AFTER 3 SECONDS
                    c1.getImg().setImageResource(R.drawable.facedown);
                    c2.getImg().setImageResource(R.drawable.facedown);
             }
             };

             thread.start();
        }
    }
}

 @Override
 public boolean onTouchEvent(MotionEvent evt) {
 if (evt.getAction() == MotionEvent.ACTION_DOWN) {
 synchronized (thread) {
 thread.notifyAll();
 }
 }
 return true;
 }

09-07 17:04:19.937: E/AndroidRuntime(6822): FATAL EXCEPTION: Thread-4693
09-07 17:04:19.937: E/AndroidRuntime(6822): android.view.ViewRootImpl$CalledFromWrongThreadException: Only the original thread that created a view hierarchy can touch its views.
09-07 17:04:19.937: E/AndroidRuntime(6822):     at android.view.ViewRootImpl.checkThread(ViewRootImpl.java:4746)
09-07 17:04:19.937: E/AndroidRuntime(6822):     at android.view.ViewRootImpl.requestLayout(ViewRootImpl.java:823)
09-07 17:04:19.937: E/AndroidRuntime(6822):     at android.view.View.requestLayout(View.java:15473)
09-07 17:04:19.937: E/AndroidRuntime(6822):     at android.view.View.requestLayout(View.java:15473)
09-07 17:04:19.937: E/AndroidRuntime(6822):     at android.view.View.requestLayout(View.java:15473)
09-07 17:04:19.937: E/AndroidRuntime(6822):     at android.view.View.requestLayout(View.java:15473)
09-07 17:04:19.937: E/AndroidRuntime(6822):     at android.widget.RelativeLayout.requestLayout(RelativeLayout.java:318)
09-07 17:04:19.937: E/AndroidRuntime(6822):     at android.view.View.requestLayout(View.java:15473)
09-07 17:04:19.937: E/AndroidRuntime(6822):     at android.widget.ImageView.setImageResource(ImageView.java:352)
4

1 回答 1

1

声明c1和c2作为全局变量。

private Thread thread;

President c1, c2;

public void checkMatch(int num) {
    flips++;
    c1 = null;
    c2 = cards.get(num - 1);
    ....
    ....
}

编辑：

您正在尝试从非 UI 线程更改 UI。而不是以下内容：

thread = new Thread() {
         @Override
         public void run() {
             try {
                 synchronized (this) {
                     wait(3000);
                 }
             } catch (InterruptedException ex) {
         }

         // TODO
         //THESE TWO LINES ARE THE ONES I WANT TO RUN AFTER 3 SECONDS
                c1.getImg().setImageResource(R.drawable.facedown);
                c2.getImg().setImageResource(R.drawable.facedown);
         }
         };

         thread.start();

使用处理程序：

new Handler().postDelayed(new Runnable() {

    @Override
    public void run() {
        c1.getImg().setImageResource(R.drawable.facedown);
        c2.getImg().setImageResource(R.drawable.facedown);
    }
}, 3000L);
于 2013-09-07T21:01:55.267 回答