3

我最近试图制作一个能够编码和解码 Base64 以及其他“语言”(如十六进制和二进制)的 iOS 应用程序。我试图制作一个自动解码器(能够自动检测“语言”)。但是,当我使用 Base64 时,自动解码器似乎无法检测到有效的 Base64,因为 Base64 字符串中有换行符。我的 Base64 检测代码如下所示:

-(BOOL)isBase64Data:(NSString *)input
{
    if ([input length] % 4 == 0) {
        static NSCharacterSet *invertedBase64CharacterSet = nil;
        if (invertedBase64CharacterSet == nil) {
            invertedBase64CharacterSet = [[NSCharacterSet characterSetWithCharactersInString:@"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/="]invertedSet];
        }
        return [input rangeOfCharacterFromSet:invertedBase64CharacterSet options:NSLiteralSearch].location == NSNotFound;
    }
    return NO;
}

只是为了获得更多信息,这是我在 NSString 中检测“语言”类型的方法。

-(NSInteger)detectType:(BOOL)base64 hexadecimal:(BOOL)hex binary:(BOOL)binary
{
    //Make sure the checking of characters are in this order!
    if (binary) {
        return 0; //Type 0 means binary
    }
    else if (hex) {
        return 1; //Type 1 means hexadecimal
    }
    else if (base64) {
        return 2; //Type 2 means base64
    }
    else {
        return 3; //Type 3 is error/invalid text
    }
}

每当我想解码时,我都会调用此方法:

-(IBAction)decode:(id)sender
{
    //This is where I detect the type
    NSInteger type = [self detectType:[self isBase64Data:userInput.text] hexadecimal:[self isHexadecimal:userInput.text] binary:[self isBinary:userInput.text]];

    if ([userInput text].length<1) { //First, check if the text view is empty in the first place
        WCAlertView *alert=[[WCAlertView alloc]initWithTitle:@"Error: No input!" message:nil delegate:nil cancelButtonTitle:@"Okay" otherButtonTitles:nil, nil];
        [alert show];
    }
    else if (type==0) {
        //Initiate the binary converter here
        TextBinViewController *binVC=[[TextBinViewController alloc]init];
        output.text=[binVC binToText:userInput.text];
    }
    else if (type==1) {
        //Initiate the hexadecimal converter here
        TextHexViewController *hexVC=[[TextHexViewController alloc]init];
        output.text=[hexVC hexToText:userInput.text];
    }
    else if (type==2) {
        //Initiate the base64 converter here
        TextBase64ViewController *baseVC=[[TextBase64ViewController alloc]init];
        output.text=[baseVC base64Decode:userInput.text];
    }
    else {
        //If the type matches none of the above, show an error (WCAlertView is a subclass of alertview that allows more styling)
        WCAlertView *alert=[[WCAlertView alloc]initWithTitle:@"Error: Invalid input!" message:nil delegate:nil cancelButtonTitle:@"Okay" otherButtonTitles:nil, nil];
        [alert show];
        output.text=@"";
    }

    [userInput resignFirstResponder];
}
4

2 回答 2

5

好的,我意识到我可以简单地从字符串中删除所有换行符。更新后的 -isBase64Data 方法如下:

-(BOOL)isBase64Data:(NSString *)input
{

    input=[[input componentsSeparatedByCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]] componentsJoinedByString:@""];
    if ([input length] % 4 == 0) {
        static NSCharacterSet *invertedBase64CharacterSet = nil;
        if (invertedBase64CharacterSet == nil) {
            invertedBase64CharacterSet = [[NSCharacterSet characterSetWithCharactersInString:@"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/="]invertedSet];
        }
        return [input rangeOfCharacterFromSet:invertedBase64CharacterSet options:NSLiteralSearch].location == NSNotFound;
    }
    return NO;
}

现在 Base64 字符串的检测工作正常。我发现当字符串有换行符等时,[input length] % 4不会返回 0。所以,我目前的解决方案是简单地使用whitespaceAndNewlineCharacterSet.

于 2013-09-07T15:49:57.947 回答
0

在有效字符的字符串中添加一个新行,从中创建一个集合并取其逆。

于 2013-09-07T09:09:57.210 回答