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目标/tl；博士当您提交论坛并使用文本字段中的内容创建新的帖子对象时，我想从views.py 中调用我添加的方法。

我是 django 的新手，我查看了其他堆栈帖子，但大多数这些错误似乎是针对 cookie 或用户的。正如大多数人所建议的那样，我还查看了 python 文档，但我还没有看到所有的部分，我不确定如何从论坛获取文本字段。正确的代码和/或我做错了什么以及如何做的解释将不胜感激。

模型.py

from django.db import models

class Post(models.Model):
    text = models.TextField(max_length=250)
    time = models.DateTimeField(auto_now_add=True)

    def __unicode__(self):
        return self.text

视图.py

from django.http import Http404, HttpResponse
from django.shortcuts import render_to_response, redirect
from blog.models import Post
from django.core.context_processors import csrf

def home(request):
    try:
        p = Post.objects.all()
    except Post.DoesNotExist:
        raise Http404
    return render_to_response('index.html',
        {'post':p})

def post(request, uID):
    try:
        p = Post.objects.get(pk=uID)
    except:
        raise Http404
    return render_to_response('post.html',
        {'post':p})

def delete(request, uID):
    try:
        p = Post.objects.get(pk=uID).delete()
    except:
        raise Http404
    return render_to_response('delete.html',
        {'post':p})

def new(request):
    context = {}
    context.update(csrf(request))
    return render_to_response('new.html', context)

def added(request):
    if request.method == 'POST':
        context = {}
        context.update(csrf(request))
        p = Post.objects.create(text=request.text)
        p.save()
        return render_to_response("index.html", context)
    else:
        raise Http404

网址.py

from django.conf.urls import patterns, include, url


from django.contrib import admin
admin.autodiscover()

urlpatterns = patterns('',
    url(r'^$', 'blog.views.home', name='home'),
    url(r'^(?P<uID>\d+)/$', 'blog.views.post', name='Post Id'),
    url(r'^(?P<uID>\d+)/delete/$', 'blog.views.delete', name='del'),
    url(r'^new/$', 'blog.views.new'),
    url(r'^created/$', 'blog.views.added'),
    # url(r'^myApp/', include('myApp.foo.urls')),

    # Uncomment the admin/doc line below to enable admin documentation:
    # url(r'^admin/doc/', include('django.contrib.admindocs.urls')),


    url(r'^admin/', include(admin.site.urls)),
)

新的.html

<html>
    <body>
        <h2> Create a new Post </h2>
        <form method="post" action="/created/">
            {% csrf_token %}
            Body: <input type="textarea" name="text">
            <input type="submit" value="Submit">
        </form>
    </body>
</html>
4

1 回答 1

6

你的意思是request.POST['text']。

不过，您可能应该调查表单框架。

于 2013-08-22T09:48:23.207 回答