php - MYSQL 查询不是我要找的结果

Question

我有这个查询：

SELECT gamer_id,COUNT(*) AS sum, SUM(amount) as amount 
        FROM sales_list 
        WHERE rdate BETWEEN '2012-04-01' AND '2012-04-30' AND gamer_id NOT IN 
            (SELECT gamer_id FROM sales_list WHERE rdate < '2012-04-01' GROUP BY gamer_id) 
        GROUP BY gamer_id

这个查询打印了“2”个结果，而我只看到了“1”。

我有 1 个玩家在 4 月份存款 2 次，我不想计算总存款只是为了计算存款的总玩家。

有什么建议吗？

Answer 1

我真的不明白，但你想要一个游戏玩家的存款数量或他存款的金额？！

这应该提供存款数量：

SELECT gamer_id, COUNT(gamer_id) AS sum, SUM(amount) as amount 
FROM sales_list 
WHERE rdate BETWEEN '2012-04-01' AND '2012-04-30'
GROUP BY gamer_id
HAVING COUNT(gamer_id)>0

编辑：

SELECT DISTINCT gamer_id
FROM sales_list 
WHERE rdate BETWEEN '2012-04-01' AND '2012-04-30' 
AND gamer_id NOT IN  (SELECT gamer_id 
                      FROM sales_list 
                      WHERE rdate < '2012-04-01') 
GROUP BY gamer_id

Answer 2

尝试这个：

SELECT sl.gamer_id,COUNT(*) AS sum, SUM(sl.amount) as amount 
        FROM sales_list sl
        WHERE sl.rdate BETWEEN '2012-04-01' AND '2012-04-30' AND sl.gamer_id NOT IN 
            (SELECT sl1.gamer_id FROM sales_list sl1 WHERE sl1.rdate < '2012-04-01' GROUP BY sl1.gamer_id) 
        GROUP BY sl.gamer_id