根据您最近的评论,这里是一个线程的示例实现,该线程按需唤醒,运行其相应的任务,然后返回睡眠,以及管理它的必要功能(等待任务完成、请求关闭、等待关机)。
由于您的函数集是固定的,您剩下要做的就是创建所需的线程数(即 7 个,可能在 a 中vector
),每个线程都有自己相应的任务。
请注意,一旦您删除了 debug cout
,就剩下很少的代码,所以我认为没有必要解释代码(恕我直言,这是不言自明的)。但是,请不要犹豫,询问您是否需要对某些细节进行解释。
class TaskThread {
public:
TaskThread(std::function<void ()> task)
: m_task(std::move(task)),
m_wakeup(false),
m_stop(false),
m_thread(&TaskThread::taskFunc, this)
{}
~TaskThread() { stop(); join(); }
// wake up the thread and execute the task
void wakeup() {
auto lock = std::unique_lock<std::mutex>(m_wakemutex);
std::cout << "main: sending wakeup signal..." << std::endl;
m_wakeup = true;
m_wakecond.notify_one();
}
// wait for the task to complete
void wait() {
auto lock = std::unique_lock<std::mutex>(m_waitmutex);
std::cout << "main: waiting for task completion..." << std::endl;
while (m_wakeup)
m_waitcond.wait(lock);
std::cout << "main: task completed!" << std::endl;
}
// ask the thread to stop
void stop() {
auto lock = std::unique_lock<std::mutex>(m_wakemutex);
std::cout << "main: sending stop signal..." << std::endl;
m_stop = true;
m_wakecond.notify_one();
}
// wait for the thread to actually be stopped
void join() {
std::cout << "main: waiting for join..." << std::endl;
m_thread.join();
std::cout << "main: joined!" << std::endl;
}
private:
std::function<void ()> m_task;
// wake up the thread
std::atomic<bool> m_wakeup;
bool m_stop;
std::mutex m_wakemutex;
std::condition_variable m_wakecond;
// wait for the thread to finish its task
std::mutex m_waitmutex;
std::condition_variable m_waitcond;
std::thread m_thread;
void taskFunc() {
while (true) {
{
auto lock = std::unique_lock<std::mutex>(m_wakemutex);
std::cout << "thread: waiting for wakeup or stop signal..." << std::endl;
while (!m_wakeup && !m_stop)
m_wakecond.wait(lock);
if (m_stop) {
std::cout << "thread: got stop signal!" << std::endl;
return;
}
std::cout << "thread: got wakeup signal!" << std::endl;
}
std::cout << "thread: running the task..." << std::endl;
// you should probably do something cleaner than catch (...)
// just ensure that no exception propagates from m_task() to taskFunc()
try { m_task(); } catch (...) {}
std::cout << "thread: task completed!" << std::endl;
std::cout << "thread: sending task completed signal..." << std::endl;
// m_wakeup is atomic so there is no concurrency issue with wait()
m_wakeup = false;
m_waitcond.notify_all();
}
}
};
int main()
{
// example thread, you should really make a pool (eg. vector<TaskThread>)
TaskThread thread([]() { std::cout << "task: running!" << std::endl; });
for (int i = 0; i < 2; ++i) { // dummy example loop
thread.wakeup();
// wake up other threads in your thread pool
thread.wait();
// wait for other threads in your thread pool
}
}
这是我得到的(实际顺序因运行而异,具体取决于线程调度):
main: sending wakeup signal...
main: waiting for task completion...
thread: waiting for wakeup or stop signal...
thread: got wakeup signal!
thread: running the task...
task: running!
thread: task completed!
thread: sending task completed signal...
thread: waiting for wakeup or stop signal...
main: task completed!
main: sending wakeup signal...
main: waiting for task completion...
thread: got wakeup signal!
thread: running the task...
task: running!
thread: task completed!
thread: sending task completed signal...
thread: waiting for wakeup or stop signal...
main: task completed!
main: sending stop signal...
main: waiting for join...
thread: got stop signal!
main: joined!