我有一个带有 3 个片段的 SherlockFragmentActivity。一切正常，但是当我从一个片段滑动到另一个片段时，会显示错误的菜单。Fragment1 显示来自 fragment2 的菜单，Fragment1 上的 SearchView 正在过滤 Fragment2 上的数据。这是 SherlockFragmentActivity 的代码
public class MainHolder extends SherlockFragmentActivity {
private static final String[] CONTENT = new String[] { "FRAGMENT1", "FRAGMENT2", "FRAGMENT3" };
FragmentAdapter mAdapter;
ViewPager mPager;
TabPageIndicator mIndicator;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main_holder);
mAdapter = new FragmentAdapter(getSupportFragmentManager());
mPager = (ViewPager)findViewById(R.id.pager);
mPager.setAdapter(mAdapter);
mIndicator = (TabPageIndicator)findViewById(R.id.indicator);
mIndicator.setViewPager(mPager);
}
class FragmentAdapter extends FragmentPagerAdapter {
public FragmentAdapter(FragmentManager fm) {
super(fm);
}
public Fragment getItem(int position) {
switch(position)
{
case 0:
return Fragment1.newInstance(CONTENT[position % CONTENT.length]);
case 1:
return Fragment2.newInstance(CONTENT[position % CONTENT.length]);
case 2:
return Fragment3.newInstance(CONTENT[position % CONTENT.length]);
default:
return null;
}
}
@Override
public CharSequence getPageTitle(int position) {
return CONTENT[position % CONTENT.length].toUpperCase();
}
@Override
public int getCount() {
return CONTENT.length;
}
}
@Override
public void onBackPressed() {
Fragment fragment = (Fragment) getSupportFragmentManager().findFragmentByTag("android:switcher:" + R.id.pager + ":"+mPager.getCurrentItem());
if (fragment != null) // could be null if not instantiated yet
{
if (fragment.getView() != null) {
// Pop the backstack on the ChildManager if there is any. If not, close this activity as normal.
if (!fragment.getChildFragmentManager().popBackStackImmediate()) {
finish();
}
}
}
}
}
这是片段
public class Fragment1 extends SherlockFragment {
private static final String KEY_CONTENT = "Fragment1:Content";
LazyAdapter fragment1adapter;
@Override
public void onCreateOptionsMenu(Menu menu, MenuInflater inflater) {
super.onCreateOptionsMenu(menu, inflater);
menu.clear();
inflater.inflate(R.menu.fragment1, menu);
MenuItem searchItem = menu.findItem(R.id.menu_search);
final SearchView searchView = (SearchView) searchItem.getActionView();
searchView.setQueryHint("Pretraga ...");
searchView.setOnQueryTextListener(new SearchView.OnQueryTextListener() {
@Override
public boolean onQueryTextChange(String newText) {
if (newText.length() != 0) {
fragment1adapter.getFilter().filter(newText);
return true;
}
return false;
}
@Override
public boolean onQueryTextSubmit(String query) {
return false;
}
});
searchView.setOnCloseListener(new SearchView.OnCloseListener() {
@Override
public boolean onClose() {
fragment1adapter.getFilter().filter("");
return false;
}
});
}
public static Fragment1 newInstance(String content) {
Fragment1 fragment = new Fragment1();
StringBuilder builder = new StringBuilder();
for (int i = 0; i < 20; i++) {
builder.append(content).append(" ");
}
builder.deleteCharAt(builder.length() - 1);
fragment.mContent = builder.toString();
return fragment;
}
private String mContent = "???";
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
if ((savedInstanceState != null) && savedInstanceState.containsKey(KEY_CONTENT)) {
mContent = savedInstanceState.getString(KEY_CONTENT);
}
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View v = inflater.inflate(R.layout.fragment1, container, false);
setRetainInstance(true);
setHasOptionsMenu(true);
setMenuVisibility(true);
}
@Override
public void onSaveInstanceState(Bundle outState) {
super.onSaveInstanceState(outState);
outState.putString(KEY_CONTENT, mContent);
}
}
其他片段是相同的，具有单独的菜单和布局。谁能给我一些提示，为什么会这样？