等式1:
solve({a^2+b^2+169+sqrt(c-13)-24*a-10*b = 0},{a, b, c})
assuming a>0, b>0, c>0;
//a=12, b=5, c=13
等式2:
solve([1/(cos(a)^2)+1/(sin(a)^2*sin(b)^2*cos(b)^2) = 9,
a>0, a<Pi/2, b>0, b<Pi/2], [a,b,c] );
//a=arctan(sqrt(2)), b=Pi/4
我上面已经累了,但是maple无法给出解决方案,我是否使用不正确的解决方案?