我有这个问题,我从第一个活动窗口启动第二个活动窗口,我需要直接查看凸轮预览>拍摄快照>在此活动窗口上显示预览。
现在,这就是我需要启动它的方式(用户需求的预期和正确方式),但是在拍照并回到这个窗口之后,应用程序几乎就这样崩溃了。
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
this.imageView = (ImageView)this.findViewById(R.id.picture);
Button photoButton = (Button) this.findViewById(R.id.capture_btn);
//photoButton.setOnClickListener(new View.OnClickListener() {
//@Override
//public void onClick(View v) {
Intent cameraIntent = new Intent(android.provider.MediaStore.ACTION_IMAGE_CAPTURE);
startActivityForResult(cameraIntent, CAMERA_REQUEST);
// }
//});
}
但是这样它就不会崩溃,这样它的错误用例就会导致它变成我的应用程序的两个按钮。
public class MainActivity extends Activity implements OnClickListener {
private static final int CAMERA_REQUEST = 1888;
private static final int PIC_CROP = 0;
private ImageView imageView;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
this.imageView = (ImageView)this.findViewById(R.id.picture);
Button photoButton = (Button) this.findViewById(R.id.capture_btn);
photoButton.setOnClickListener(new View.OnClickListener() {
//@Override
public void onClick(View v) {
Intent cameraIntent = new Intent(android.provider.MediaStore.ACTION_IMAGE_CAPTURE);
startActivityForResult(cameraIntent, CAMERA_REQUEST);
}
});
}
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
if (requestCode == CAMERA_REQUEST && resultCode == RESULT_OK) {
Bitmap photo = (Bitmap) data.getExtras().get("data");
imageView.setImageBitmap(photo);
}
}
@Override
public void onClick(View arg0) {
// TODO Auto-generated method stub
}
}