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我在使用正方形大小的平铺缓冲区平铺图像缓冲区时遇到问题。请指出,我做错了什么。

想法是在某些条件下获得一个填充有预定义方形 Tile 缓冲区的图像缓冲区。以便输出图像缓冲区使用 Tile 正确耕作,请记住,图像可以是矩形(不是正方形)

谢谢你。

我试过这个。

static int imgwidth = 150; static int imgheight=100;
    static int gl_fxf = 4;//4*n
    byte[] img_byte8rgbbuff = new byte[imgwidth*imgheight*3];// variable size
    byte[] tile_byte8rgbbuff = new byte[gl_fxf * gl_fxf * 3];// can be of any size 4nX4n

    public byte[] fillwithtile(byte[] in_Image, byte[] Tile)

    {
        byte[] img_byte8rgbbuff_OUT = new byte[in_Image.Length];


        int someMainIndex;


        Action<int, int, int> TFfxMethod = (int a_h, int b_w, int in_indx) =>
        {

            int t_indx;
            //int t_indx2;

            int counter = 0;

            for (int j = a_h; j < a_h + gl_fxf; j++)
                for (int i = b_w; i < b_w + gl_fxf; i++)
                {
                    t_indx = j * 3 * imgwidth + i * 3;
                    // SOMETHING WRONG IN INDEX CALCULATION FOR ARRAYS
                    if (in_Image[in_indx] == 255)// EX. some condition in_Image[in_indx] == 255 RED component
                    {
                        img_byte8rgbbuff_OUT[t_indx] = Tile[counter];
                        img_byte8rgbbuff_OUT[t_indx+1] = Tile[counter+1];
                        img_byte8rgbbuff_OUT[t_indx+2] = Tile[counter+2];

                    }
                    counter = counter + 1;
                }

        };


        for (int palboxH = 0; palboxH <= imgheight; palboxH = palboxH + gl_fxf)
            for (int palboxW = 0; palboxW <= imgwidth; palboxW = palboxW + gl_fxf)
            {

                someMainIndex = palboxH * 3 * gl_fxf * imgwidth + palboxW * 3 * gl_fxf;

                TFfxMethod(palboxH, palboxW, someMainIndex);


            }
return img_byte8rgbbuff_OUT;

    }// 
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1 回答 1

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我自己想通了

计数器应该遵循代码,不需要 in_indx

 counter = counter +3;
于 2013-07-11T06:03:54.207 回答