sql - sql Number of Rows into one row

Question

I have two tables with these columns:

Table 1:

ID ,   INT
NAME,  NVARCHA
ROLL,  INT

Table 2:

ID,        INT 
NAME_ID,   INT
REAL_DATE, Date
H7_00,     BIT
H8_00,     BIT

I want to get a list of names of those that H7_00 is true like this, for a period of 3 months.

Real_Date | Name| Name | Name | Name | Name | Name | Name |Name |Name |Name |Name   
Real_Date | Name    | Name |
Real_Date | Name| Name | Name | Name    
Real_Date | Name    | Name | Name | Name |Name| Name | Name | Name  

The following is what I tried

SELECT 
    Hours.Real_Date, Person.Name ,Person.Role 
FROM  
    Person
INNER JOIN
    Hours ON Hours.P_ID = Person.ID
WHERE 
(Hours.Real_Date >=  getDate())
    AND
(Hours.Real_Date <=  getDate() + 90)
    (Hours.H7_00 = 1   AND  Hours.H7_00_Free = 1)
    AND 
    (Person.Role = 1)
ORDER BY 
    Real_Date, Name

This is what I got

 2013-12-12   AAAA  1
 2013-12-12   BBBB  1           
 2013-12-12   CCCC  1

If anyone has a solution I would appreciate it very,

And thanks in advance for reply

Answer 1

在 SQL-Server (TSQL) 中，您可以尝试DATEADD (datepart , number , date)：

(DATEADD(DAY,0,Hours.Real_Date) >= DATEADD(DAY,0,getDate()))
AND
(DATEADD(DAY,0,Hours.Real_Date) <= DATEADD(DAY,+90,getDate()))