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我有四个查询，每个查询有 6 列。除了 WHERE 子句在每种情况下略有不同之外，每个查询都是相同的。我想看到的是彼此相邻的每一列的每个查询结果以进行比较。

示例结果表标题：时间（只有一个），calls1，calls2，calls3，calls4，work1，work2，work3，work4，tele1，tele2，tele3，tele4，comm1，comm2，comm3，comm4，techs1，techs2，techs3，techs4 .

实际查询如下。请帮我做一个比较查询。吨

SELECT CONCAT(hour(opened_dt),':',floor(minute(opened_dt)/15)*15) AS time, COUNT(*)/COUNT(DISTINCT DATE(opened_dt)) AS r_calls, ROUND(AVG(work_time),2)/60 AS r_work, ROUND(AVG(tele_time),2)/60 AS r_tele, ROUND(AVG(comm_time),2)/60 AS r_comm, IFNULL(COUNT(*)/COUNT(DISTINCT DATE(opened_dt)),0)/3 AS r_techs 
FROM detail_head LEFT JOIN detail_detail ON detail_detail.detail_head_uid = detail_head.detail_head_uid 
WHERE call_origins_uid != 5 
AND DATE(opened_dt) >= (CURDATE() - INTERVAL 42 DAY) 
AND dayname(opened_dt) = 'SUNDAY' 
GROUP BY (hour(opened_dt)*100)+floor(minute(opened_dt)/15) 


SELECT CONCAT(hour(opened_dt),':',floor(minute(opened_dt)/15)*15) AS time, COUNT(*)/COUNT(DISTINCT DATE(opened_dt)) AS calls, ROUND(AVG(work_time),2)/60 AS work, ROUND(AVG(tele_time),2)/60 AS tele, ROUND(AVG(comm_time),2)/60 AS comm, IFNULL(COUNT(*)/COUNT(DISTINCT DATE(opened_dt)),0)/3 AS techs 
FROM detail_head LEFT JOIN detail_detail ON detail_detail.detail_head_uid = detail_head.detail_head_uid 
WHERE call_origins_uid != 5 
AND DATE(opened_dt) >= (CURDATE() - INTERVAL 42 DAY) 
AND dayname(opened_dt) = 'SUNDAY' 
AND call_origins_uid = 1 
GROUP BY (hour(opened_dt)*100)+floor(minute(opened_dt)/15)


SELECT CONCAT(hour(opened_dt),':',floor(minute(opened_dt)/15)*15) AS time, COUNT(*)/COUNT(DISTINCT DATE(opened_dt)) AS calls, ROUND(AVG(work_time),2)/60 AS work, ROUND(AVG(tele_time),2)/60 AS tele, ROUND(AVG(comm_time),2)/60 AS comm, IFNULL(COUNT(*)/COUNT(DISTINCT DATE(opened_dt)),0)/3 AS techs 
FROM detail_head LEFT JOIN detail_detail ON detail_detail.detail_head_uid = detail_head.detail_head_uid 
WHERE call_origins_uid != 5 
AND DATE(opened_dt) >= (CURDATE() - INTERVAL 42 DAY) 
AND dayname(opened_dt) = 'SUNDAY' 
AND call_origins_uid = 4 
GROUP BY (hour(opened_dt)*100)+floor(minute(opened_dt)/15)


SELECT CONCAT(hour(opened_dt),':',floor(minute(opened_dt)/15)*15) AS time, COUNT(*)/COUNT(DISTINCT DATE(opened_dt)) AS calls, ROUND(AVG(work_time),2)/60 AS work, ROUND(AVG(tele_time),2)/60 AS tele, ROUND(AVG(comm_time),2)/60 AS comm, IFNULL(COUNT(*)/COUNT(DISTINCT DATE(opened_dt)),0)/3 AS techs 
FROM detail_head LEFT JOIN detail_detail ON detail_detail.detail_head_uid = detail_head.detail_head_uid 
WHERE DATE(opened_dt) >= (CURDATE() - INTERVAL 42 DAY) 
AND dayname(opened_dt) = 'SUNDAY' 
GROUP BY (hour(opened_dt)*100)+floor(minute(opened_dt)/15)
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1 回答 1

1

您可以为每个表使用“CREATE TEMPORARY TABLE TableName1”，然后编写一个查询以按顺序排列列，然后在完成后删除表。

于 2013-06-18T17:35:20.977 回答