1

编辑：

 ['Station 5 average is less than 1.62644628099', 'Station 6 average is less than 1.62644628099', 'Station 7 average is less than 1.62644628099', 'Station 8 average is less than 1.62644628099', 'Station 9 average is less than 1.62644628099', 'Station 10 average is less than 1.62644628099']

和

['Station 1 average is greater than 1.62644628099', 'Station 2 average is greater than 1.62644628099', 'Station 3 average is greater than 1.62644628099']

有没有我可以用来产生结果的代码，使得打印时的输出看起来像这样

Station 5 average is less than 1.62644628099
Station 6 average is less than 1.62644628099
Station 7 average is less than 1.62644628099 
Station 8 average is less than 1.62644628099 
Station 9 average is less than 1.62644628099 
Station 10 average is less than 1.62644628099

和

Station 1 average is greater than 1.62644628099
Station 2 average is greater than 1.62644628099
Station 3 average is greater than 1.62644628099

感谢您的阅读以及您可以提供的任何建议/帮助。

4

2 回答 2

5

使用该str.join()函数，它打印列表中的每个元素，str中间是。在这里，我在每个元素之间插入一个新行。

>>> lst1 = ['Station 5 average is less than 1.62644628099', 'Station 6 average is less than 1.62644628099', 'Station 7 average is less than 1.62644628099', 'Station 8 average is less than 1.62644628099', 'Station 9 average is less than 1.62644628099', 'Station 10 average is less than 1.62644628099']
>>> print '\n'.join(lst1)
Station 5 average is less than 1.62644628099
Station 6 average is less than 1.62644628099
Station 7 average is less than 1.62644628099
Station 8 average is less than 1.62644628099
Station 9 average is less than 1.62644628099
Station 10 average is less than 1.62644628099

第二个列表相同：

>>> lst2 = ['Station 1 average is greater than 1.62644628099', 'Station 2 average is greater than 1.62644628099', 'Station 3 average is greater than 1.62644628099']
>>> print '\n'.join(lst2)
Station 1 average is greater than 1.62644628099
Station 2 average is greater than 1.62644628099
Station 3 average is greater than 1.62644628099

或者，您可以使用 for 循环：

>>> for i in lst1:
...     print i
... 
Station 5 average is less than 1.62644628099
Station 6 average is less than 1.62644628099
Station 7 average is less than 1.62644628099
Station 8 average is less than 1.62644628099
Station 9 average is less than 1.62644628099
Station 10 average is less than 1.62644628099

>>> for i in lst2:
...     print i
... 
Station 1 average is greater than 1.62644628099
Station 2 average is greater than 1.62644628099
Station 3 average is greater than 1.62644628099

使用该join()函数可能更可取，因为它实际上会返回结果，因此如果您愿意，可以稍后在代码中使用它。

于 2013-05-29T07:32:09.123 回答
1

使用换行符加入列表成员。

print "\n".join(t)
print
print "\n".join(s)
于 2013-05-29T07:31:59.687 回答