1

CASE1： 我得到以下错误：

 org.apache.jasper.JasperException: An exception occurred processing JSP page /login.jsp at line 14

11: <body>
12:     
13:     
14:      <form:form  method="get" commandName="user" action="login">
15:      
16:         <form:label path="Username" /><form:input path="uname"/>
17:         <form:label path="Password" /><form:input path="password"/>


Stacktrace:
    org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:521)
    org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:424)
    org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:313)
    org.apache.jasper.servlet.JspServlet.service(JspServlet.java:260)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
root cause

java.lang.IllegalStateException: No WebApplicationContext found: no ContextLoaderListener registered?
    org.springframework.web.context.support.WebApplicationContextUtils.getRequiredWebApplicationContext(WebApplicationContextUtils.java:90)
    org.springframework.web.servlet.support.RequestContextUtils.getWebApplicationContext(RequestContextUtils.java:85)
    org.springframework.web.servlet.support.RequestContext.initContext(RequestContext.java:209)
    org.springframework.web.servlet.support.JspAwareRequestContext.initContext(JspAwareRequestContext.java:74)
    org.springframework.web.servlet.support.JspAwareRequestContext.<init>(JspAwareRequestContext.java:48)
    org.springframework.web.servlet.tags.RequestContextAwareTag.doStartTag(RequestContextAwareTag.java:77)
    org.apache.jsp.login_jsp._jspx_meth_form_005fform_005f0(login_jsp.java:111)
    org.apache.jsp.login_jsp._jspService(login_jsp.java:76)
    org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
    org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:388)
    org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:313)
    org.apache.jasper.servlet.JspServlet.service(JspServlet.java:260)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:717)

当我使用以下表格时：

<form:form  method="post" commandName="user" action="login">

        <form:label path="Username" /><form:input path="uname"/>
        <form:label path="Password" /><form:input path="password"/>

        <input type="submit" value="Submit" />
     </form:form>

CASE2： 当我提交下面的表格后，我得到了 404，我的意思是这个网址：http://localhost:8443/BugTrackingSystem/login

当我使用以下表格时：

<form action="login" method="post">
        Username: <input type="text" name="uname">
        Password: <input type="text" name="password">
        <input type="submit" value="Submit">
    </form>

其他文件： *登录控制器： *

package com.bts.controller;


import javax.servlet.ServletException;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.springframework.validation.BindException;
import org.springframework.web.servlet.ModelAndView;
import org.springframework.web.servlet.mvc.AbstractFormController;
import org.springframework.web.servlet.mvc.SimpleFormController;

import com.bts.vo.User;

public class LoginController extends SimpleFormController{


     public LoginController(){
            setCommandClass(User.class);
            setCommandName("user");
        }



     protected ModelAndView onSubmit(Object obj) throws ServletException {

         User user = (User) obj;
            System.out.println("username: "+user.getUname());


        return new ModelAndView("index","user", user);

     }


}

WEB.XML

   <?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns="http://java.sun.com/xml/ns/javaee"
    xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
    id="WebApp_ID" version="2.5">
    <display-name>BugTrackingSystem</display-name>

    <welcome-file-list>
        <welcome-file>login.jsp</welcome-file>
    </welcome-file-list>

    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/application-context.xml</param-value>
    </context-param>

    <listener>
        <listener-class>
            org.springframework.web.context.ContextLoaderListener
        </listener-class>
    </listener>

    <servlet>
        <servlet-name>dispatcher</servlet-name>
        <servlet-class>
            org.springframework.web.servlet.DispatcherServlet
        </servlet-class>
        <load-on-startup>2</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>dispatcher</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>



</web-app>

用户.JAVA

package com.bts.vo;

import java.util.ArrayList;
import java.util.List;

public class User {

    public User() {

        countries = new ArrayList<String>();

        countries.add("India");
        countries.add("US");

    }

    private String uname;
    private String password;
    private List<String> countries;

    public String getUname() {
        return uname;
    }
    public void setUname(String uname) {
        this.uname = uname;
    }
    public String getPassword() {
        return password;
    }
    public void setPassword(String password) {
        this.password = password;
    }
    public List<String> getCountries() {
        return countries;
    }
    public void setCountries(List<String> countries) {
        this.countries = countries;
    }

}

调度员-SERVLET.XML

<?xml version="1.0" encoding="UTF-8"?>

<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:p="http://www.springframework.org/schema/p"
    xsi:schemaLocation="
        http://www.springframework.org/schema/beans     
        http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
        http://www.springframework.org/schema/context 
        http://www.springframework.org/schema/context/spring-context-3.0.xsd">


    <bean id="viewResolver"
        class="org.springframework.web.servlet.view.InternalResourceViewResolver" p:order="1">
        <property name="prefix">
            <value>/WEB-INF/jsp/</value>
        </property>
        <property name="suffix">
            <value>.jsp</value>
        </property>
    </bean>     


</beans>

控制器-Beans.XML

<?xml version="1.0" encoding="UTF-8"?>

<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:p="http://www.springframework.org/schema/p"
    xsi:schemaLocation="
        http://www.springframework.org/schema/beans     
        http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
        http://www.springframework.org/schema/context 
        http://www.springframework.org/schema/context/spring-context-3.0.xsd">



    <bean name="login" class="com.bts.controller.LoginController">
        <property name="successView" value="index" />
    </bean>

    <bean name="productDetails"
        class="com.bts.controller.ProductDetailsController">
    </bean>



</beans>

应用程序上下文.xml

<?xml version="1.0" encoding="UTF-8"?>

<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:p="http://www.springframework.org/schema/p"
    xsi:schemaLocation="
        http://www.springframework.org/schema/beans     
        http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
        http://www.springframework.org/schema/context 
        http://www.springframework.org/schema/context/spring-context-3.0.xsd">

  <import resource="dispatcher-servlet.xml"/>
  <import resource="controllers-beans.xml"/>
  <import resource="datasource.xml"/>
  <import resource="hibernate-beans.xml"/>


</beans>

我现在正在学习Spring，所以我面临上述问题，所以请给我一个解决方案，等我了解这个问题后我会使用Annotations..

4

1 回答 1

0

我推荐以下链接：

http://duckranger.com/2012/04/spring-mvc-dispatcherservlet/

http://viralpatel.net/blogs/spring-3-mvc-handling-forms/

http://static.springsource.org/spring/docs/2.0.x/reference/mvc.html

这个设置对我有用：

web.xml

<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/applicationContext.xml</param-value>
    </context-param>
    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>
    <servlet>
        <servlet-name>dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>2</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>dispatcher</servlet-name>
        <url-pattern>*.htm</url-pattern>
    </servlet-mapping>
    [...]
</web-app>

application-context.xml

<beans xmlns="http://www.springframework.org/schema/beans">
    <import resource="myOtherContext.xml"/>
</beans>

myOtherContext.xml（为了有一些进口）

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:p="http://www.springframework.org/schema/p"
    xsi:schemaLocation="
        http://www.springframework.org/schema/beans     
        http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
        http://www.springframework.org/schema/context 
        http://www.springframework.org/schema/context/spring-context-3.0.xsd">

    <bean name="login" class="test.LoginController"/>
</beans>

dispatcher-context.xml（请注意，这是自动寻址的，因为我的调度程序 servlet 被调用dispatcher并-context.xml自动附加）

<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:p="http://www.springframework.org/schema/p"
       xmlns:aop="http://www.springframework.org/schema/aop"
       xmlns:tx="http://www.springframework.org/schema/tx"
       xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
       http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.0.xsd
       http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd">

    <bean class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping"/>

    <bean id="urlMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
        <property name="mappings">
            <props>
                <prop key="index.htm">index</prop>
                <prop key="login.htm">login</prop>
            </props>
        </property>
    </bean>

    <bean id="viewResolver"
          class="org.springframework.web.servlet.view.InternalResourceViewResolver"
          p:prefix="/WEB-INF/jsp/"
          p:suffix=".jsp" />

    <bean name="index"
          class="org.springframework.web.servlet.mvc.ParameterizableViewController"
          p:viewName="index" />

</beans>

login.jsp

<%@page contentType="text/html" pageEncoding="UTF-8"%><%@ taglib prefix="form" uri="http://www.springframework.org/tags/form"%>
<!DOCTYPE html>
<html>
    <head>
        <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
        <title>Login</title>
    </head>
    <body>
        <form:form  method="post" commandName="user" action="login.htm">
        <form:label path="uname" /><form:input path="uname"/>
        <form:label path="password" /><form:input path="password"/>
        <input type="submit" value="Submit" />
     </form:form>
    </body>
</html>

LoginController.java

public class LoginController extends SimpleFormController {

    public LoginController() {
        setCommandClass(User.class);
        setCommandName("user");
    }

    @Override
    protected org.springframework.web.servlet.ModelAndView showForm(HttpServletRequest request, HttpServletResponse response, BindException errors, Map controlModel) throws Exception {

        return super.showForm(request, response, errors, controlModel);
    }

    @Override
    protected ModelAndView onSubmit(Object obj) throws ServletException {

        User user = (User) obj;
        System.out.println("username: " + user.getUname());
        return new ModelAndView("index", "user", user);
    }
}
于 2013-05-27T08:34:37.403 回答