1

任何人都可以让我知道如何阅读目录并找到该目录中的文件和目录。

我尝试使用以下is_dir()函数检查目录

$main = "path to the directory";//Directory which is having some files and one directory
readDir($main);

function readDir($main) {
    $dirHandle = opendir($main);
    while ($file = readdir($dirHandle)) {
        if ($file != "." && $file != "..") {
            if (is_dir($file)) {
                 //nothing is coming here
            }
        }
    }
}

但它不检查目录。

谢谢

4

6 回答 6

1

您必须使用子目录的完整路径：

if(is_dir($main.'/'.$file)) { ... }
于 2012-09-12T09:32:53.407 回答
1

PHP 5 中最简单的方法是使用RecursiveDirectoryIteratorand RecursiveIteratorIterator：

$dir = '/path/to/dir';
$directoryIterator = new RecursiveDirectoryIterator($dir);

$iterator = new RecursiveIteratorIterator($directoryIterator, RecursiveIteratorIterator::CHILD_FIRST);

foreach ($iterator as $path) {
  if ($path->isDir()) {
     // ...
  }
}

您不需要自己递归，因为这些优秀的迭代器自己处理它。

有关这些强大的迭代器的更多信息，请参阅链接的文档文章。

于 2012-09-12T09:35:32.923 回答
0 
$le_map_to_search = $main;
$data_to_use_maps[] = array();
$data_to_use_maps = read_dir($le_map_to_search, 'dir');
$aantal_mappen = count($data_to_use_maps);
$counter_mappen = 1;
while($counter_mappen < $aantal_mappen){
   echo $data_to_use_maps[$counter_mappen];
   $counter_mappen++;
}

$data_to_use_files[] = array();
$data_to_use_files = read_dir($le_map_to_search, 'files');
$aantal_bestanden = count($data_to_use_files);
$counter_files = 1;
while($counter_files < $aantal_files){
   echo $data_to_use_files [$counter_files ];
   $counter_files ++;
}
于 2012-09-12T09:31:45.250 回答
0

尝试这个
$handle = opendir($directory); //Open the directory
while (false !== ($file = readdir($handle))) {
$filepath = $directory.DS.$file; //Get all files/directories in the directory
}

于 2012-09-12T09:46:17.373 回答
0

使用scandir 然后解析结果并消除'.' 和 '..' 和is_file()

于 2012-09-12T09:28:15.487 回答
0

看看这里的参考：

http://php.net/manual/en/function.scandir.php

于 2012-09-12T09:33:20.643 回答