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我需要根据用户的登录在我的模板中显示不同的按钮。场景是我的模板显示跟随按钮：

Check whether the user logged in or not-
  if user logged in-
   check which channel he follwed:
     if he followed any channel 
       beside that channel name show "followed" button
     else
       show "follow" button with the path follow_save 
  elif user not logged in:
     show follow button with the path follow_save

我被卡住了怎么办？这是视图任务还是模板任务？怎么做？你们专家的任何帮助都会救我..我也想从会话中获取 user_id。这是我的意见.py

e= EventArchiveGallery.objects.all()   
user = request.session['user_id']
if user:
    j = EventArchiveGallery()
    joining_list = j.joiningList(user)         

return render_to_response('gallery/allevents.html',
{
    'joining_list':joining_list,
},
context_instance=RequestContext(request)                         
)

这是我的模板：

{% for event in live %}
    <p>Event Title:{{event.event_title}}<p/>
    <p>Channel Name:{{event.channel_id.channel_title}}</p>
    <p>Event Description{{event.event_description}}</p>
    {% if event in joining_list %}
        <p>followed</p>
            {%else%}
                    <p>follow</p> #I have wanted to show follow_save function call from this button,when user clicked
            {endif%}
  {% endfor %}
4

1 回答 1

0

无论如何，如果你可以分成 2 个问题，你会更好地问 2 个问题......

  • 根据用户的登录在我的模板中显示不同的按钮
    • 更好的方法是确定要在视图中显示的内容并将上下文参数传递给模板。根据这个变量模板将呈现不同的 HTML。

示例模板：假设视图传递followed_channel参数。

{% if user.is_authenticated %}
    {%if followed_channel %}
        {# render html you want #}
    {%else%}
        {# render another way #}
    {%endif%}
{%endif%}
  • 我也想从会话中获取 user_id

在从会话中获取之前，您必须存储它。因此，您可以将视图更新为

e= EventArchiveGallery.objects.all()   
user = request.session.get('user_id')
if not user:
     request.session['user_id'] = request.user.id
if user:
    j = EventArchiveGallery()
    joining_list = j.joiningList(user)         

return render_to_response('gallery/allevents.html',
{
    'joining_list':joining_list,
},
context_instance=RequestContext(request)                         
)
于 2012-09-12T09:54:37.553 回答