按下 capture 后Button
,图像应该保存在 sdcard 中,它正在拍摄快照但不保存图像,那么我怎样才能将捕获按钮放在我想要的任何地方?我有一个覆盖层,Imageview
我需要将按钮放在覆盖层上。
问问题
224 次
3 回答
1
int 图片回调,这样使用
jpegCallback = new PictureCallback() {
public void onPictureTaken(byte[] data, Camera camera) {
camera.startPreview();
FileOutputStream outStream = null;
try {
outStream = new FileOutputStream(
"/mnt/sdcard/myphoto.jpg");
outStream.write(data);
outStream.close();
Log.d("Log", "onPictureTaken - wrote bytes: " + data.length);
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} finally {
}
Log.d("Log", "onPictureTaken - jpeg");
}
};
于 2013-05-21T08:02:05.960 回答
1
使用这个将图像存储在 sd 卡中
public void save(Bitmap image)
{
File sdcard = Environment.getExternalStorageDirectory();
File f = new File (sdcard, imagename);
FileOutputStream out=null;
try {
out = new FileOutputStream(f);
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
image.compress(Bitmap.CompressFormat.PNG, 90, out);
try {
out.flush();
out.close();
} catch (IOException e) {
e.printStackTrace();
}
}
于 2013-05-21T08:04:53.413 回答
0
stream=new ByteArrayOutputStream();
temBitmap=Bitmap.createBitmap(bmp);
temBitmap.compress(Bitmap.CompressFormat.JPEG,100, stream);
path+=String.format(
getString(R.string._sdcard_d_jpg),
System.currentTimeMillis());
outStream = new FileOutputStream(path+extension); // <9>
outStream.write(stream.toByteArray());
outStream.close();
以这种方式更改上面的代码段:
path+=String.format(
getString(R.string._sdcard_d_jpg),
System.currentTimeMillis());
outStream = new FileOutputStream(path+extension); // <9>
temBitmap=Bitmap.createBitmap(bmp);
temBitmap.compress(Bitmap.CompressFormat.JPEG,100, outStream);
outStream.close();
temBitmap.recycle()
于 2013-05-21T08:04:59.993 回答