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我正在使用SQLITE我的 iPhone 应用程序。在中插入值后detailedViewController，我正在masterViewController viewWillAppear方法中重新加载数据库中的数据。但是，除非我重新启动应用程序，否则我无法在那里获得新更新的行。我正在完成编译的语句并在INSERT.

sqlite3_finalize(compiledStatement);
sqlite3_close(database);

关于我可能做错了什么的任何指示？

if(sqlite3_open([dbPath UTF8String], &database) == SQLITE_OK) {
        const char *sqlStatement = "SELECT * FROM MYCAR1";
        sqlite3_stmt *compiledStatement;
        if(sqlite3_prepare_v2(database, sqlStatement, -1, &compiledStatement, NULL) == SQLITE_OK) {

            while(sqlite3_step(compiledStatement) == SQLITE_ROW) {
                //...getting data from compiled statements...

                MyCar *car=[[MyCar alloc] initWithVIN:vin.intValue andMake:make andModel:model andYear:year andColor:color andImageData:image];
                [myArray addObject:car];
            }
        }
        sqlite3_finalize(compiledStatement);
        carList=myArray;
    }
    sqlite3_close(database);

    [self.tableView reloadData];
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1 回答 1

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我添加了用于选择的确切代码，这对我有用。尝试将此与您的代码进行比较并找出错误。

sqlite3 *database;

if(sqlite3_open([databasePath UTF8String], &database)==SQLITE_OK)
{

    NSString *querySql=[NSString stringWithFormat:@"Select * from xxx"];

    const char *sqlStatement=[querySql UTF8String];

    sqlite3_stmt *compiledStatement;

    if(sqlite3_prepare_v2(database, sqlStatement, -1, &compiledStatement, NULL) == SQLITE_OK) {
        // Loop through the results and add them to the your array

        while(sqlite3_step(compiledStatement) == SQLITE_ROW)  {
           //get the data from db here                


        }

        sqlite3_finalize(compiledStatement);
    }

    sqlite3_close(database);
于 2013-04-04T08:03:53.810 回答