嗨,我正在尝试使用 php 脚本将三个下拉列表中的“post”值传递到数据库,在该脚本中,我使用三个列表的值将值插入数据库
以前我使用 jquery ajax 调用从另一个页面将列表检索到 div time.php
看起来像这样的代码:-
//This script uses jquery and ajax it is used to set the values in
// the time field whenever a day is selected.
$(document).ready(function(){
$("#day").change(function(){
var day=$("#day").val();
var doctor=$("#doctor").val();
$.ajax({
type:"post",
url:"time.php",
data:"day="+day+"&doctor="+doctor,
success:function(data){
$("#time").html(data);
}
});
});
});
html 部分的代码如下所示:-
<select id="doctor">some options</select>
<select id="day">some options</select>
<div id="time"> </div>
现在两个列表中的值都很好。但是我检索到 div 的那个没有通过。你能指出我正确的方向吗?提前致谢。
//The php script for insertion
<?php
session_start(); //Use this to include session variables
$con=mysqli_connect("localhost","clinic","myclinic","myclinic");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$query = "INSERT INTO appointment(username, doctor, day, time) VALUES('$_SESSION[username]', '$_POST[doctor]', '$_POST[day]', '$_POST[time]')";
if (!mysqli_query($con,$query))
{
die('Error: ' . mysqli_error($con));
}
mysqli_close($con);
header("location:login_success.php");
?>