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正如标题所暗示的，我遇到了一个switch语句未能检查循环i内的变量for某个值的问题。下面的布尔函数模拟两个精灵之间的定向边界框碰撞，i变量代表定向边界框的每个面。但是，当函数返回时false，i仅在值0和处检查1，而当函数返回时true，i仅在值2和处检查3。

我不知道是for循环还是switch语句导致了这个错误，我已经仔细检查了碰撞是否在定向边界框的所有面上都有效，我可以确认它确实完美无缺。任何形式的帮助将不胜感激！

碰撞.cpp：

bool Collision::orientedBoundingBoxTest(const sf::Sprite &object1, const sf::Sprite &object2, int object1Width, int object1Height, int object2Width, int object2Height)
{
    /*Variables assigned and declared here*/

    for (int i = 0; i < 4; i++)
    {
        float faceX = collisionObject1.getPoint(i).x - collisionObject1.getPoint((i + 1) % 4).x;
        float faceY = collisionObject1.getPoint(i).y - collisionObject1.getPoint((i + 1) % 4).y;

        float perpendicularAxisX = -faceY;
        float perpendicularAxisY = faceX;

        float normalizedAxisLength = sqrt(perpendicularAxisX * perpendicularAxisX + perpendicularAxisY * perpendicularAxisY);
        perpendicularAxisX /= normalizedAxisLength;
        perpendicularAxisY /= normalizedAxisLength;

        float object1Min = std::numeric_limits<float>::max(), object1Max = -object1Min;
        float object2Min = std::numeric_limits<float>::max(), object2Max = -object2Min;

        for(int j = 0; j < 4; j++)
        {
            float object1Projection = (perpendicularAxisX * (collisionObject1.getPoint(j % 4).x + collisionObject1.getPosition().x) + perpendicularAxisY * (collisionObject1.getPoint(j % 4).y + collisionObject1.getPosition().y)) / (perpendicularAxisX * perpendicularAxisX + perpendicularAxisY * perpendicularAxisY);
            object1Min = min(object1Projection, object1Min);
            object1Max = max(object1Projection, object1Max);
        }

        for(int j = 0; j < 4; j++)
        {
            float object2Projection = (perpendicularAxisX * (collisionObject2.getPoint(j % 4).x + collisionObject2.getPosition().x) + perpendicularAxisY * (collisionObject2.getPoint(j % 4).y + collisionObject2.getPosition().y)) / (perpendicularAxisX * perpendicularAxisX + perpendicularAxisY * perpendicularAxisY);
            object2Min = min(object2Projection, object2Min);
            object2Max = max(object2Projection, object2Max);
        }

        switch (i) //Switch statement failing to check "i" variable at certain values
        {
        case 0:
            deltaY = -(object1Max - object2Min);
            break;
        case 1:
            deltaX = object1Min - object2Max;
            break;
        case 2:
            deltaY = object1Min - object2Max;
            break;
        case 3:
            deltaX = -(object1Max - object2Min);
            break;
        }

        if (! (object1Max >= object2Min && object1Min <= object2Max))
            return false;
    }
    return true;
}

引擎.cpp：

void Engine::physics(sf::RenderWindow& _window)
{
    for (int i = 0; i < 5; i++)
    {
        if (collision.orientedBoundingBoxTest(collisionArray[i].collisionObjectSprite, player.playerSprite, collisionArray[i].width, collisionArray[i].height, player.width, player.height))
        {
            currentCollisionObjectIndex = i;
            player.hitTest = true;
            break;
        }
        else
        {
            player.hitTest = false;
        }
    }

    /*Additional code here*/
}
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1 回答 1

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在我看来，你的结论是错误的，放在scout << i << endl;之间case，并确保你的结果。

我确信每个0..3迭代都会在每个迭代 ot 上遇到i，除非return调用该语句。

   switch (i)
    {
    case 0:
        deltaY = -(object1Max - object2Min); cout << i << endl;
        break;
    case 1:
        deltaX = object1Min - object2Max; cout << i << endl;
        break;
    case 2:
        deltaY = object1Min - object2Max; cout << i << endl;
        break;
    case 3:
        deltaX = -(object1Max - object2Min); cout << i << endl;
        break;
    }
于 2013-03-11T20:21:35.440 回答